<img src="https://tex.z-dn.net/?f=%285x%20-%202%29%20%5Ctimes%20%28x%20%20%2B%202%29" id="TexFormula1" title="(5x

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Alexxx [7]

3 years ago

+ 2)" alt="(5x - 2) \times (x + 2)" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Mars2501 [29]3 years ago

4 0

Answer:

5x^2 +8x-4

Step-by-step explanation:

(5x - 2) * (x + 2)

We can FOIL

first: 5x*x = 5x^2

outer : 2*5x = 10x

inner: -2x

last : -2*2 = -4

Add these together

5x^2 +10x-2x-4

5x^2 +8x-4

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If a school bought 3 cheese pizzas and 1 pepperoni pizza how many cheese and pepperonis pizzas did they get if they bought 6 che

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3 years ago

A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, $q_1 = Q- r \times Q$

$q_1 = Q(1-r)\cdots(i)$

The value of quantity after 2 months, $q_2 = q_1- r \times q_1$

$q_2 = q_1(1-r)$

From equation (i)

$q_2=Q(1-r)(1-r) \\\\q_2=Q(1-r)^2\cdots(ii)$

The value of quantity after 3 months, $q_3 = q_2- r \times q_2$

$q_3 = q_2(1-r)$

From equation (ii)

$q_3=Q(1-r)^2(1-r)$

$q_3=Q(1-r)^3$

Similarly, the value of quantity after n months,

$q_n= Q(1- r)^n$

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

$q_{48}=Q(1-r)^{48}$

Putting Q=6200 and r=5.5%=0.055, we have

$q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32$

Hence, the value of quantity after 4 years is 410.32.

4 0

3 years ago

Read 2 more answers

A and B are independent events. P(A) = 0.50 P(B) = 0.30 What is P(A/B)? a. not enough information. b. 0.30 c. 0.50 d. 0.15

Gala2k [10]

Answer:

0.50

Step-by-step explanation:

P(A|B)=P(A and B)/P(B) is the formula to find a conditional probability when A and B are not independent.

A and B are independent. This means B has no effect of A. This means P(A|B)=P(A).

P(A|B)=P(A) since A and B are independent

P(A|B)=0.50

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3 years ago

HELPPPP JUST 2 QUESTIONS BASED ON PYTHAGOREAN THEOREM AND IM CONFUSED HELPPPP

Anna007 [38]

9514 1404 393

Answer:

3. no; does not have the correct ratio to other sides

4. (1; right), (2; obtuse), (3; right)

Step-by-step explanation:

3. There are a couple of ways you can go at this.

a) the ratio of sides of a 30°-60°-90° right triangle (half an equilateral triangle) is 1 : √3 : 2. Here, the ratio of sides is ...

(√30/2) : √15 : √30 = 1 : √2 : 2 . . . . MQ is not the height

b) the height is perpendicular to the base, so if MQ were the height, the sides of the triangle would satisfy the Pythagorean theorem:

LQ² +MQ² = LM²

(√30/2)² +(√15)² = (√30)²

30/4 +15 = 30

22.5 = 30 . . . . NOT TRUE

The length MQ cannot be the height of ∆LMN. (It is too short.)

4. To see if these lengths form a right triangle, you can test them in the Pythagorean theorem relation. In the attached we have reformulated the equation so it gives a value of 0 if the triangle is a right triangle:

c² = a² +b² . . . . . Pythagorean theorem

c² -a² -b² = 0 . . . . rewritten

If the value of c² -a² -b² is not zero, then the side lengths do not form a right triangle. The attached shows this math performed by a graphing calculator. The results are ...

right triangle
not a right triangle — long side is too long, so the triangle is obtuse
right triangle

_____

Additional comment

The attached table demonstrates an artifact of computer arithmetic. Not all numbers can be represented exactly in a computer, so a difference that is expected to be zero using exact arithmetic may be slightly different from zero when computed by a computer or calculator. Here, we see a difference of about 6×10^-14 when zero is expected. On most calculators (with 10, or 12 displayed digits), this would be displayed as 0.

The same calculation done "by hand" gives ...

(√425)² -5² -20² = 425 -25 -400 = 0 . . . Triangle 1 is a right triangle

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3 years ago

Simplify . 4y4 4y8 8y4 8y8

Tanya [424]

Answer:

Step-by-step explanation:

Just did it.

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3 years ago