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Sholpan [36]
2 years ago
14

What is the sum of the first seven terms of the geometric series where a1 = 10 and r = −2?

Mathematics
1 answer:
lbvjy [14]2 years ago
5 0

Answer:

  • 430

Step-by-step explanation:

<h3>Given GP with:</h3>
  • a1 = 10
  • r = -2
<h3>To find</h3>
  • S7
<h3>Solution</h3>

<u>Formula of sum:</u>

  • Sn = a1(r^n - 1)/(r - 1)

<u>Substitute values:</u>

  • S7 = 10((-2)^7 - 1)/(-2 - 1) = 10(- 128 - 1)/(-3) = 10*129/3 = 430
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F(x) = 5 + 2x  where x is the number of times he walks the neighbours dog
y-intercept is at y=5 and slope = 2

g(x) :-  As x increases by 4 g(x) decreases by -8  so the slope is -8/4 =  -2
when x = 0, g(x)  = the y intercept  is at -1 + (-8/2) = - 5
so equation of g(x) is  g(x) = -5 -2x
h(x):-    the slope is  (3 - 5) / (1 - 0)      [  difference in y values / diff in x values]
slope = -2
so we have h(x) = -2x + c   where c = the y-intercept
when x = 0  h(x) = 5
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8 0
3 years ago
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Using the image above, if the density of the LEGO piece is 0.85 g/cm^3, what COULD be a possible measurement for the density of
grin007 [14]

The Lego is submerged under the oil and therefore, is more dense than the oil

The possible density of the oil is the option;

<u>0.79 g/cm³</u>

Reason:

Given:

The density of Lego = 0.85 g/cm³

Density of oil = Required

Solution:

The density of an object is the mass per unit volume it occupies

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Increase in density increases the mass a unit volume occupies, therefore, a

more dense object is heavier than a less dense object such that the less

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The oil is floating on the Lego, therefore, the Lego is more dense than the

oil, and we have;

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The density of Lego = 0.85 g/cm³

Therefore;

0.85 g/cm³ > Density of oil

From the given options, the option that has a density less than 0.85 g/cm³ is the the option 0.79 g/cm³

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<u />

Learn more here:

brainly.com/question/12864420

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2 years ago
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ELEN [110]
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