3 years ago

In square ABCD, AC = 3(x+8) and BD = 7 +4x. Solve for X

Mathematics

1 answer:

svetoff [14.1K]3 years ago

7 0

Answer:

x=17

Step-by-step explanation:

3(x+8) = 7+4x

3x+24 = 7+4x

24 = 7+x

17=x

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Find the value of x such that the area of a triangle whose vertices have coordinates (6, 5), (8, 2) and (x, 11) is 15 square uni

Serjik [45]

Answer:

$x =12\ or\ -8$

Step-by-step explanation:

Given

$(x_1,y_1) = (6,5)$

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Required

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Substitute values

$15 = \frac{1}{2}|6*(2 - 11) + 8*(11 - 5) + x(5 - 2)|$

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Multiply through by 2

$2 * 15 = \frac{1}{2}|-6 + 3x| * 2$

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Remove absolute sign

$30 = -6 + 3x\ or\ -30 = -6 + 3x$

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$x =12\ or\ -8$

<em>So, the coordinates are (-8, 11) or (12,11)</em>

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3 years ago

Can someone please help me with 2 and explain the steps to 3 thanks!

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Answer:

#2 is a ratio so you gotta add.

#3 it’s just adding it for example 2p + 5a = 7pa

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3 years ago