Answer is 279
Step-by-step explanation:
Lets do the following:
How many 1/9 are there in 1? Easy! 9. We can corroborate this by summing 1/9 nine times of multiplying 1/9 nine times. In both cases the result is 9.
Then, how many 1 are there in 31? Easier!! 31. Is we sum the number 1 thirty one times, the result is 31.
Now let join both results:
If each 1 has nine 1/9, and there are thirty one 1s in 31, then in 31 we have 31*9=279 1/9s. This is:
31*1 = 31 * 9 (1/9) = 279 * (1/9)
Answer:
the interquartile range is 7
Explanation: Just like any of your two-step equations,
in this inequality, start by isolating the x term which in this
case is -3x by subtracting 5 from both sides.
That leaves you with -3x < -24.
To get x by itself, divide both sides by -3 but watch out.
When you multiply or divide both sides of an inequality by a
negative number, you must switch the direction of the inequality sign.
So we have x < 8 and put your final answer in
set notation and it look like this → {x: x < 8}.
Answer:
M = -7
Step-by-step explanation:
It makes sense if you replace it in for M! Hope this helps and have a great day!
7^2 - 3(4-2)^0 - 2(7+3) + 3^2
= 49 - 3 - 20 + 9
= 35
hope it helps
P.S
any number to the 0 power is always equal 1
