Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
Answer:
Explanation:
1. By driving 6 miles each, the cars will be 6 miles + 6 miles = 12 miles appart.
2. When one car stops and the other car makes a 90° left-hand turn and drive 8 miles, you can model the situation with a right triangle, where one leg is 12 miles, the other leg is 8 miles, and the hypotenuse is the distance that separates the cars.
Hence, you must use Pythagoras to find that distance.
3. Pythagoras
- hypotenuse² = leg₁² + leg₂²
- hypotenuse = (12 mile)² + (8 mile)² = 144 mile² + 64 mile² = 208 mile²
, which is rounded to the neartest tenth of a mile.
Answer:
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There are a couple of ways to tackle this one, using the 45-45-90 rule or just using the pythagorean theore, let's use the pythagorean theorem.
the angle at A is 45°, and its opposite side is BC, the angle at C is 45° as well, and its opposite side is AB, well, the angles are the same, thus BC = AB.
hmmm le'ts call hmmm ohh hmmm say z, thus BC = AB = z.
The answer is b. If your problem is y=1/2x-3