Question

When using the identity for the sum of two cubes to factor 125q^6-r^6s^3

Answer 1

Answer:

a = 5q²

b = r²s

Step-by-step explanation:

The given identity is $a^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})$

we have to use this identity to factor of two cubes given as $125q^{6}-r^{6}s^{3}=(5q^{2})^{3}-(r^{2}s)^{3}$

As this expression is in the form of a³- b³

Here a is 5q² and b is r²s.