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jasenka [17]
2 years ago
5

Write an equation of the line perpendicular to the x-axis and passes through (4,-3)

Mathematics
2 answers:
abruzzese [7]2 years ago
7 0

Answer:

y=-x+1

Step-by-step explanation:

Firdavs [7]2 years ago
4 0

Step-by-step explanation:

The equation of the line is x = 4.

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Step-by-step explanation:

6 0
3 years ago
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Pls help! Show all work. Will reward the brainiest for da best answer.
BaLLatris [955]

Answer:

1. 56.52 inches

2. 141,300 inches

Step-by-step explanation:

One turn of the tire is the circumference. Therefore, we have to find the circumference first. C = πd = 18π = 18 × 3.14 = 56.52 in

2500 rotations would be 2500 ⋅ 56.52 in = 141,300 in

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4 0
2 years ago
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
2 years ago
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