Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
<span>2.5<span>(<span><span>6x</span>−4</span>)</span></span>=<span><span><span><span><span>(10)</span><span>(4)</span></span><span>(1.5)</span></span><span>(0.5)</span></span><span>x
</span></span><span><span><span><span>(2.5)</span><span>(<span>6x</span>)</span></span>+<span><span>(2.5)</span><span>(<span>−4</span>)</span></span></span>=<span><span><span><span><span>(10)</span><span>(4)</span></span><span>(1.5)</span></span><span>(0.5)</span></span>x</span></span>(Distribute)<span><span><span><span>15x</span>+</span>−10</span>=<span>30x
</span></span><span><span><span>15x</span>−10</span>=<span>30<span>x
</span></span></span><span><span><span><span>15x</span>−10</span>−<span>30x</span></span>=<span><span>30x</span>−<span>30x</span></span></span><span><span><span>−<span>15x</span></span>−10</span>=<span>0
</span></span><span><span><span><span>−<span>15x</span></span>−10</span>+10</span>=<span>0+10</span></span><span><span>−<span>15x</span></span>=<span>10
</span></span><span><span><span>−<span>15x</span></span><span>−15</span></span>=<span>10<span>−15</span></span></span><span>x=<span><span>−2</span><span>3
</span></span></span>Answer:<span>x=<span><span>−2</span><span>3</span></span></span>
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The statements true about the the function f(x) = 2x2 – x – 6 are-
- The vertex of the function is (one-quarter, negative 6 and one-eighth).
- The function has two x-intercepts.
<h3>What is vertex of parabola?</h3>
The vertex of parabola is the point at the intersection of parabola and its line of symmetry.
Now the given function is,
f(x) = 2x^2 – x – 6
Also, it is given that the vertex is located at (0.25, -6) and the parabola opens up, the function has two x-intercepts.
Comparing the given function with standard form,
f(x) = a x^2 bx + c
By comprison we get,
a = 2
b = -1
c = -6
Now, x-coordinate of vertex is given as,
x = -b/2a
put the values we get,
x = -(-1)/2*2
or, x = 1/4
Put the value of x in given function, so y-coordinate of the vertex is given as,
f(1/4) = 2(1/4)² - 1/4 - 6
= -49/6
= -6 1/8
Hence, The statements true about the the function f(x) = 2x2 – x – 6 are-
- The vertex of the function is (one-quarter, negative 6 and one-eighth).
- The function has two x-intercepts.
More about vertex :
brainly.com/question/86393
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Yes.??? dont really Know sorry
Answer:
C $1.75
Step-by-step explanation:
$469 divided by 268 is $1.75, so it's $1.75 per item
