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Margaret [11]
3 years ago
9

một kho hàng có 927 chiếc quạt, đã chuyển đi 1/9 số quạt đó. Hỏi kho hnag còn lại bao nhiêu chiếc quạt?

Mathematics
1 answer:
skad [1K]3 years ago
8 0

Answer:

824

Step-by-step explanation:

Số quạt đã chuyển đi:

927 x 1/9 = 103 (chiếc)

Số quạt còn lại trong kho hàng là:

927-103 = 824 (chiếc)

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a floor is 450 ft by 90 ft. A scale drawing of the floor on grid paper uses a scale of 1 unit:5 feet. what are the dimensions of
Minchanka [31]
450/5= 90 units

90/5= 18 units

All you need to do is divide the real dimensions by the scale dimensions, and turn that answer to units. Notice: It said 1 unit: 5 feet

The scale drawing was 90 to 18 units.

I hope this helps!
~kaikers
8 0
3 years ago
Solving Exponential Equations (lacking a common base)<br> 31^d=38
Bond [772]

Answer:

d = log 38/log31

d = 1.06

Step-by-step explanation:

31 ^ d = 38

Take log of both sides since the exponential equation have different base (always)

d log 31 = log 38

d = log 38 / log 31

d = 1.58 / 1.491

d = 1.06.

We can actually check to see if this is correct.

Substituting d = 1.06

31^ 1.06 = 38.092

(You see, that's approximately correct)

Keep learning, maths is fun!

8 0
3 years ago
A company has recently been hiring new employees. Today the company has 34% more employees than it did a year ago. If there are
Anton [14]

Answer:

22110 employees.

Step-by-step explanation:

33500 decrease 34% =

33500 × (1 - 34%) = 33500 × (1 - 0.34) = 22110

5 0
3 years ago
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A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Der
taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
<span>   Σ (2i + 3)
</span>i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
The table and the graph each show a different relationship between the same two variables, x and y:
Inessa05 [86]

Answer:

275

Step-by-step explanation:

3 0
2 years ago
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