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Nina [5.8K]
4 years ago
6

I need help, im a single dad construction worker from los angeles, my daughter is a very smart person. Im having trouble correct

ing a wrong answer in math. She goes to Kumon academy for math and reading, but this problem im out of words

Mathematics
1 answer:
Deffense [45]4 years ago
6 0

Answer:

B=210

C=450

Step-by-step explanation:

Since you are asking for number 8, let's work with that problem :)

Firstly, we have to know we have rectangles here, and the area of a rectangle is given by the following formula:

A_{rectangle}=(width)(height)

So, in this problem we are given as an example the rectangle A, with witdth 90 and height 30. So, its area is:

A=(90)(30)=2700

The same happens with the small rectangle B:

B=(7)(5)=35

And, we have to do the same with rectangles B and C:

<u>Rectangle B:</u>

Width:7

Height:30

B=(7)(30)=210

<u>Rectangle C:</u>

Width:90

Height:5

B=(90)(5)=450

If we sum A, B, C and D the result must be equal to the total are of the big rectangle:

A+B+C+D=2700+210+450+35=3395

Area of big rectangle with width 90+7=97 and height 30+5=35:

(97)(35)=3395

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You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e
victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = \dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}

mean = 15.58

the standard deviation \sigma = \sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}

the standard deviation = \sqrt{\dfrac{(26.2  - 15.58)^2 +(27.7 - 15.58)^2 +(8.6  - 15.58)^2 + (3.8  - 15.58)^2  + (11.6  - 15.58)^2  }{5 }  }

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = t \times \dfrac{\sigma}{\sqrt{n}}

The Margin of Error M.O.E = 1.533 \times \dfrac{9.62297}{\sqrt{5}}

The Margin of Error M.O.E = 1.533 \times 4.3035

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( \mu  \pm M.O.E )

The  Confidence interval = ( \mu  +  M.O.E , \mu - M.O.E )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

7 0
3 years ago
2(x 4) = 35 − (7 − 4x)
Rus_ich [418]
2(x4) = 35 - (7-4x)
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2(x8)= 28
/2         /2
8x = 14

6 0
3 years ago
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