Answer:
b ASA
Step-by-step explanation:
Answer:
Can you show me a picture of the problem??
Step-by-step explanation:
Answer: ![19,461\ ft^3](https://tex.z-dn.net/?f=19%2C461%5C%20ft%5E3)
Step-by-step explanation:
The missing figure is attached.
The volume of grain that could completely fill this silo is the sum of the volume of the cylinder and the volume of the hemisphere.
By definition, the volume of a cylinder can be calculated with this formula:
![V_c=\pi r^2h](https://tex.z-dn.net/?f=V_c%3D%5Cpi%20r%5E2h)
Where "r" is the radius and "h" is the height.
In this case you know that:
![r=6\ ft\\\\h=168\ ft](https://tex.z-dn.net/?f=r%3D6%5C%20ft%5C%5C%5C%5Ch%3D168%5C%20ft)
And the volume of a hemisphere can be found using the following formula:
![V_h=\frac{2}{3} \pi r^3](https://tex.z-dn.net/?f=V_h%3D%5Cfrac%7B2%7D%7B3%7D%20%5Cpi%20r%5E3)
Where "r" is the radius.
In this case:
![r=6\ ft](https://tex.z-dn.net/?f=r%3D6%5C%20ft)
Therefore, the volume of grain that could completely fill this silo, rounded to the nearest whole number, is:
![V_{grain}=(\frac{22}{7})(6\ ft)^2 (168\ ft)+\frac{2}{3} (\frac{22}{7})(6\ ft)^3\\\\V_{grain}\approx19,461\ ft^3](https://tex.z-dn.net/?f=V_%7Bgrain%7D%3D%28%5Cfrac%7B22%7D%7B7%7D%29%286%5C%20ft%29%5E2%20%28168%5C%20ft%29%2B%5Cfrac%7B2%7D%7B3%7D%20%28%5Cfrac%7B22%7D%7B7%7D%29%286%5C%20ft%29%5E3%5C%5C%5C%5CV_%7Bgrain%7D%5Capprox19%2C461%5C%20ft%5E3)
Hii!!
I think that the correct answer would be C. I know that it couldn't be A because not everyone in 2nd period got 100% and the average students got below 95%. B no because they do not have the same median. D, I do not think so at all. So I would go with C I think it is relatively the best answer!!
Hope that helps!1
I am very sorry to say but I see no equations for this question. Also, I suppose the question must be either x = -6 and y=2 or x=2 and y=-6.