Well the position function is:
h(t)=-16t^2+256
It will hit the ground when h(t)=0
-16t^2+256=0 factor out -16
-16(t^2-16)=0 factor difference of squares...
-16(t+4)(t-4)=0, since t>0
t=4 seconds
Hello :
(-6a)-(-3a) =(-3a)-(0) = (0)-(3a) = (3a)-(6a) = -3a (arthmetic<span> sequence, the common - diff is : d= -3a the first term is : U1 = 6a
</span><span>a general rule for the n th term is : Un =U1+(n-1)d
Un = 6a +(n-1)(-3a) =
Un = 6a -3an+3a
</span>Un = -3an +9a
Answer:
4b
Step-by-step explanation:
The line of symmetry can never be symmetrical. If you put a vertical line through the middle the sides aren't equal. Same for horizontal and diagonal.
Question: Terri wrote the system of linear inequalities.
-3x - 3y > -18
-X<-y
Select all of the ordered pairs that are part of the solution set for this system of linear inequalities.
A: (-1,5)
B: (2, 4)
C: (3, 3)
D: (4.6)
E: (5,2)
Answer: A,b,d