If 1 uniform costs $ 20....and there are 14 players....then Fritz would spend
(20 x 14) = $ 280.....thats if each player only gets 1 uniform .
Answer:
Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and
respectively.
Step-by-step explanation:
Given that,
For the first 9 holes X:
E(X) = 80
SD(X)=13
For the second 9 holes Y:
E(Y) = 80
SD(Y)=13
For the sum W=X+Y, the following properties holds for means , variance and standard deviation :
E(W)=E(X)+E(Y)
and
V(W)=V(X)+V(Y)
⇒SD²(W)=SD²(X)+SD²(Y) [ Variance = (standard deviation)²]

∴E(W)=E(X)+E(Y) = 80 +80=160
and
∴



Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and
respectively.
Answer: 75
Step-by-step explanation:
I'm not sure if interpreted your wording correctly but this is what I got...
w(4)+6=8
From the graph, we can actually see that as the altitude increase, the
value of the pressure decreases. Or if we say it the opposite way, as the
altitude decreases (approaches sea level), the pressure increases, therefore
the answer is:
As the altitude approaches sea level, the atmospheric
pressure increases.