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3 years ago

If Laura were able to find a 0 iron, about how far could she hit it?

Mathematics

1 answer:

Katarina [22]3 years ago

7 0

Answer:

I got 219 but I'm not sure that's the answer.

Step-by-step explanation:

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Eloy went shopping and bought 2 shirts for $12.95 each, a pair of pants for $35.89, and a hat for $11.47. Eloy paid with a $100

grin007 [14]

Answer:

26.74

Step-by-step explanation:

(12.95x2)+35.89+11.47=73.26

100-73.26=26.74

7 0

3 years ago

Tell if the ratios form a proportion

Slav-nsk [51]

Answer:

True

Step-by-step explanation:

$\frac{11}{12} = \frac{33}{36} \\ or \: 11 : 12 = 33 : 36(multiplying \: by \: 3)$

5 0

3 years ago

Read 2 more answers

Can someone help please

pickupchik [31]

Negative association. There is an outlier, the data moves positively, and there is a large cluster in the graph data.

6 0

3 years ago

Ten more than 6 times Harold age is the same as 4 times his age is increased by 40. Find Harold’s age

frez [133]

100 because 6x10 is 60 and when u add 40 because you increase it is 100

4 0

3 years ago

A simplified model for the movement of the price of a stock supposes that on each day the stock’s price either moves up 1 unit w

DanielleElmas [232]

Answer:

(a) The probability that after 2 days the stock will be at its original price is

$P_a=2p(1-p)$

(b) The probability that after 3 days the stock’s price will have increased by 1 unit is

$P_b=3p^2(1-p)$

(c) Given that after 3 days the stock’s price has increased by 1 unit, the probability that it went up on the first day is

$P=2/3$

Step-by-step explanation:

(a) What is the probability that after 2 days the stock will be at its original price?

For the price of the stock to be in its original price, there are two ways it can happen:

1) the price increases the first day by one unit and decreases by one unit the second day. The probability of this event is P=p*(1-p).

2) the price decreases the first day by one unit and increases by one unit the second day. The probability of this event is P=(1-p)p.

The probability that after 2 days the stock will be at its original price is the sum of the probability of this two events:

$P=P_1+P_2=p(1-p)+(1-p)p=2p(1-p)$

(b) What is the probability that after 3 days the stock’s price will have increased by 1 unit?

For this event to happen (one unit increase in 3 days), it must have happened 2 increases in price and 1 decrease.

There are 3 possible ways of this to happen:

1) decrease in the first day.

2) decrease in the second day.

3) decrease in the third day.

Each one ot this 3 events has the same probability $P_i=p^2(1-p)$ .

So the probability that after 3 days the stock’s price will have increased by 1 unit is equal to the sum of the probabilities of this events:

$P=P_1+P_2+P_3=3p^2(1-p)$

(c) Given that after 3 days the stock’s price has increased by 1 unit, what is the probability that it went up on the first day?

According to the answer (c), there are 3 events where the price has increase by one unit after 3 days, each one with equal probability $P_i=p^2(1-p)$ .

Of these 3 events, there are 2 that have an increase in the first day. So we can conclude that, if the events have the same probability, the probability of the increase in the first day, given that the price has increased by one unit in 3 days, is P=2/3.

8 0

4 years ago

If Laura were able to find a 0 iron, about how far could she hit it?​

If Laura were able to find a 0 iron, about how far could she hit it?