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3 years ago

Can someone help please

Mathematics

1 answer:

pickupchik [31]3 years ago

6 0

Negative association. There is an outlier, the data moves positively, and there is a large cluster in the graph data.

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Find the value of x A. 30 B. 40 C. 50 D. 60

Greeley [361]

Answer:

B. 40

Step-by-step explanation:

We can make this an equation since the entire thing equals 360

3x+110+90+40=360

3x=120

x=40

Answer is B

Brainliest please :)

6 0

3 years ago

Yuri thinks that 3/4 is a root of the following function.

sineoko [7]

Given:

The polynomial function is

$q(x)=6x^3+19x^2-15x-28$

Yuri thinks that $\dfrac{3}{4}$ is a root of the given function.

To find:

Why $\dfrac{3}{4}$ cannot be a root?

Solution:

We have,

$q(x)=6x^3+19x^2-15x-28$

If $\dfrac{3}{4}$ is a root, then the value of the function at $\dfrac{3}{4}$ is 0.

Putting $x=\dfrac{3}{4}$ in the given function, we get

$q(\dfrac{3}{4})=6(\dfrac{3}{4})^3+19(\dfrac{3}{4})^2-15(\dfrac{3}{4})-28$

$q(\dfrac{3}{4})=6(\dfrac{27}{64})+19(\dfrac{9}{16})-\dfrac{45}{4}-28$

$q(\dfrac{3}{4})=3(\dfrac{27}{32})+\dfrac{171}{16}-\dfrac{45}{4}-28$

$q(\dfrac{3}{4})=\dfrac{81}{32}+\dfrac{171}{16}-\dfrac{45}{4}-28$

Taking LCM, we get

$q(\dfrac{3}{4})=\dfrac{81+342-360-896}{32}$

$q(\dfrac{3}{4})=\dfrac{-833}{32}\neq 0$

Since the value of the function at $\dfrac{3}{4}$ is not equal to 0, therefore, $\dfrac{3}{4}$ is not a root of the given function.

4 0

3 years ago

On a map, 1 inch equals 25 miles. Two cities are 4 inches apart on the map. What is the actual distance between the cities?

sleet_krkn [62]

Answer:

100 Miles

Step-by-step explanation:

If 1 inch = 25 Miles

Take 1*4 = 4 Inches

Then take 25 * 4 = 100 Miles

3 0

3 years ago

Read 2 more answers

What is the multiplicative rate of change of the function???

laiz [17]

Answer:
i think its 2/3

8 0

3 years ago

Factor the following function g(x) = x^2 + 9x + 18

qwelly [4]

Answer:

(x+6)(x+3)

Step-by-step explanation:

The factors of 18 that sum to 9 are 6 and 3, so:

(x+6)(x+3)

7 0

3 years ago