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klasskru [66]
3 years ago
15

Drag each tile to the correct box.

Mathematics
2 answers:
Citrus2011 [14]3 years ago
7 0

Answer:

<u>This is the order:</u>

1. 3x

2. 3x + 8

3. x^2

4. x^2 + 6

5. 4^x

6. 4^x + 3

(I numbered them only so it would be easier to refer to them)

Step-by-step explanation:

<u>Why is Equation #2 greater than Equation #1? </u>

This is because the equations are the same, except that the second equation is shifted up by eight units. This means that its value is always going to be eight units greater.

This same reasoning applies to Equations 3&4 and 5&6.

<u>Why is Equation #3 greater than Equation #2?</u>

This is because a certain value multiplied by three (even with eight added) will soon be overtaken by that value squared. For example, let's make x= 5

3(5) + 8 = 23

(5)^2 = 25

As you can see, the equation x^2 is already greater in value than 3x + 8.

<u>Why is Equation #5 greater than Equation #4?</u>

This is because a certain value squared will soon be overtaken by 4 to the power of that value. For example, let's make x= 2

(2)^2 + 6= 10

4^2 = 16

As you can see, the equation 4^x is already greater in value than x^2 + 6.

Hope this helps! :)

lawyer [7]3 years ago
7 0

Answer:

1. 3x

2. 3x + 8

3. x^2

4. x^2 + 6

5. 4^x

6. 4^x + 3

Step-by-step explanation:

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Veseljchak [2.6K]

Answer:

Yamateh kudasai

Step-by-step explanation:

hope it helps

8 0
2 years ago
Solve -5y+8= -3y+10 what is the answer
statuscvo [17]
-3y+10=-5y+8  add 5y to both sides

2y+10=8  subtract 10 from both sides

2y=-2  divide both sides by 2

y=-1
5 0
3 years ago
A computer retail store has 1414 personal computers in stock. A buyer wants to purchase 33 of them. Unknown to either the retail
Lorico [155]

Answer:

a) 364 ways

b) 45.33% probability that exactly one of the computers will be defective.

c) 54.67% probability that at least one of the computers selected is defective.

Step-by-step explanation:

The computers are chosen without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

14 computers, so N = 14.

3 defective, so k = 3.

3 will be purchesed, so n = 3.

A) In how many different ways can the 3 computers be chosen?

3 from a set of 14. So

C_{14,3} = \frac{14!}{3!(14-3)!} = 364

364 ways

B) What is the probability that exactly one of thecomputers will be defective?

This is P(X = 1).

P(X = 1) = h(1,14,3,3) = \frac{C_{3,1}*C_{11,2}}{C_{14,3}} = 0.4533

45.33% probability that exactly one of the computers will be defective.

C) What is the probability that at least one of the computers selected is defective?

Either none is, or at least one is. The sum of the probabilities of these events is 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = 0) = h(0,14,3,3) = \frac{C_{3,0}*C_{11,3}}{C_{14,3}} = 0.4533

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.4533 = 0.5467

54.67% probability that at least one of the computers selected is defective.

5 0
3 years ago
The vertices of ΔABC are (-2,0), (-2, 3), and (-5, 1). T(x,y) = (x + 1, 3y) represents the transformation of the triangle. What
Gnoma [55]

using the equation for the transformation:

(x+1, 3y)

 add 1 to very X and multiply y by 3

 so (-2,0) becomes (-1,0)

(-2,3) becomes (-1,9)

(-5,1) becomes (-4,3)

new coordinates are (-1,0) (-1,9) (-4,3)


you don't have an image attached, so to see if they are congruent, the sides need to stay the same lengths and the angles need to stay the same, from the coordinates of the new triangle, I would say they are not congruent

8 0
3 years ago
Mateo and Logan finished 65% of their math homework. If it has 20 problems, how many problems have they done?​
frosja888 [35]

Answer:

1st question: 13 questions

2nd question: Mr.Philps will not have enough

Step-by-step explanation:

Mateo and Logan finished 65% of their math homework. If it has 20 problems, how many problems have they done?​

20 x 0.65 = 13

Mr. Philps made 1 gallon of fruit punch for his class party. If he has 27 students, and each of them will drink 1 cup, will he have enough?

1 gallon = 16 cups

27 students x 1 cup each = 27 cups

27 is greater than 16, so no, he will not have enough.

4 0
3 years ago
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