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3 years ago

9

In Amy’s backyard, there are also chicken and rabbits, and there are 2 more chickens than rabbits. The total number of legs is 1

24. How many rabbits and how many chickens?

2 answers:

Y_Kistochka [10]3 years ago

8 0

124 divided by two is 62. so 58 and 60 would be the answers

Finger [1]3 years ago

3 0

17.75 because 125 divided by 8 is 17.75

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Hmm it would have seem that I'm in need of help here help with this

inn [45]

To find out the answer,we can test it out one by one:

The original expression: 6×(2+8)=60

A. 6x(8+2)= 6x10 = 60✅

B. (6×2)+8 = 24+8 = 34

C. (8+2)x6 = 10×6 = 60✅

D. 6x2÷6×8 =12÷6×8 = 2×8 = 16

As A. and C. equals to the original expression, the answer is A. and C.

5 0

3 years ago

Round 726.1851 to the nearest tenth.

IgorC [24]

Answer:

E

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please help! Anyone who knows about SSS, SAS, ASA, and AAS theorems.

umka21 [38]

Answer:

Step-by-step explanation:

Given:

∠C ≅ ∠E

Statements Reasons

1). ∠C ≅ ∠E 1). Given

2). ∠ABC ≅ ∠DBE 2). Vertically opposite angles

3). ΔABC ~ ΔDBE 3). By AA postulate of similarity.

5 0

3 years ago

A rectangle has an area of 2020cm².

Nadya [2.5K]

Answer:

Length = 2020 units

Width = 1 unit

Step-by-step explanation:

We know that area of a rectangle = length x width

We also know that perimeter = (2 x Length) + (2 x Width)

the goal is to to find Length and Width such that:

Condition 1: Length x width = 2020

Condition 2: (2 x Length) + (2 x Width)= maximum possible

We are also given that both Length and Width are whole numbers, hence we can start by finding the factors of 2020 into prime factors

Factor 2020: 2 x 2 x 5 x 101

By observation, we can see that the following combinations of the factors make up the required area of 2020:

Case 1: (1) x (2)(2)(5)(101) = 1 x 2020 = 2020

Perimeter = 2(1 + 2020) = 4042

Case 2: (2) x (2)(5)(101) = 2 x 1010 = 2020

Perimeter = 2(2+ 1010) = 2024

Case 3: (2)(2) x (5)(101) = 4 x 505 = 2020

Perimeter = 2(4 + 505) = 1018

Case 4: (2)(2)(5) x (101) = 20 x 101 = 2020

Perimeter = 2(20 + 101) = 242

Case 5: (5) x (2)(2)(101) = 5 x 404 = 2020

Perimeter = 2(5 + 404) = 818

Case 6: (2)(5) x (2)(101) = 10 x 202 = 2020

Perimeter = 2(10 + 202) = 424

From the above, it is clear that case 1 yields the largest perimeter

4 0

4 years ago

The perimeter of a square must be greater than 102 inches but less than 138 inches. Find the range of possible side lengths that

liberstina [14]

Answer:

s ∈ (25.5,34.5)

''s'' is in inches unit

s ∈ IR

Step-by-step explanation:

We know that the perimeter of a square is $P=4s$

Where P is the perimeter and s is the length of a side.

We want the perimeter to be greater than 102 inches but less than 138 inches.

We can write :

102 inches < P < 138 inches

If we replace P = 4s in the expression :

102 inches < 4s < 138 inches

Dividing by ''4''

25.5 inches < s < 34.5 inches

If we want the perimeter to be greater than 102 inches but less than 138 inches the length of a side must be greater than 25.5 inches but less than 34.5 inches.

Writing this in interval notation

s ∈ (25.5,34.5)

s ∈ IR

4 0

3 years ago