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Radda [10]
3 years ago
14

Solve 5n +3>27

Mathematics
1 answer:
Mama L [17]3 years ago
4 0
<h3>Hey there! </h3><h3 /><h3>\bold{5n+3>27}\\ \bold{SUBTRACT\ 3\ to\ BOTH\ SIDES}\\\bold{5n+3-3=27-3}\\\bold{24-3=24}\\\bold{Cancel\ out\ 3-3\ because\ that\ gives\ you\ 0}\\\bold{New\ equation: 5n>24}\\\bold{DIVIDE\ 5\ to\ BOTH\ SIDES}\\\bold{\dfrac{5n}{5}=\dfrac{24}{5}}\\\bold{Cancel\ out: \dfrac{5}{5}\ because\ that\ equals\ 0}\\\\ \\\\ \boxed{\boxed{\bold{Answer: n=\dfrac{24}{5}}}}\huge\checkmark</h3><h3 /><h3>Good luck on your assignment and enjoy your day! </h3><h3 /><h3>~\frak{LoveYourselfFirst:)}</h3>
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When we evaluate a logarithm, we are finding the exponent, or <u>    power   </u>  x, that the  <u>   base   </u> b, needs to be raised so that it equals the <u>  argument   </u> m. The power is also known as the exponent.

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The value of b must be <u>   positive    </u> and not equal to <u>   1   </u>

The value of m must be <u>   positive   </u>

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A <u>   logarithmic  </u>    <u>   equation  </u> is an equation with a variable that includes one or more logarithms.

===============================================

Explanation:

Logarithms, or log for short, basically undo what exponents do.

When going from 5^2 = 25 to \log_5(25) = 2, we have isolated the exponent.

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\log_b(m) = \frac{\log(m)}{\log(b)}

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