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lbvjy [14]
3 years ago
6

The diagram above shows a circle with centre O and radius 25 cm.

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer:

Step-by-step explanation:

Notice that KL = LM and PQ = QR since OL and OQ are perpendicular to both KM and PR.

It follows that QR = (1/2) PR = 20 cm. We also know that MR = 21.

Now in order to solve the problem we just need OQ=OL

OQ^2=OR^2-QR^2= 25^2-20^2 =225\\OQ=15

Therefore the perimeter of the pentagon is

OL+LM+MR+RQ+Q)\\= 15+20+21+20+15= 91

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<em>Volume</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>sphere</em><em> </em><em>is</em><em> </em><em>36</em><em>π</em><em> </em><em>(</em><em>or</em><em>)</em><em> </em><em>113</em><em>.</em><em>097</em><em> </em><em>cubic</em><em> </em><em>centimetre</em><em>. </em>

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given \\ diameter \: of \: sphere = 6 \: cm \\ radius \: of \: sphere \:  =  \frac{diameter}{2}  \\ radius \:  =  \frac{6}{2}  \\ radius \: (r) =  \: 3 \: cm \\ volume \: of \: sphere \:  =  \frac{4}{3} \pi \:  {r}^{3}  \\ here \: r \:  = 3 \: cm \\ on \: substituting \: r \:  = 3 \:  \: in \: formula \\ volume \: of \: sphere \:  =  \frac{4}{3} \pi \:  {3}^{3}  \\  \:  \:  =  \frac{4}{3} \pi \: 27 \\   \:   = \: 4 \pi \times 9 \\  \:  \:  = 36\pi \\  \:  \:  = 113.097 \:  {cm}^{3}

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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