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fenix001 [56]
3 years ago
6

5C%3A%20b%29%20%7B%7D%5E%7B3%7D%20%20%3D%20%20%7B%3F%7D%20" id="TexFormula1" title=" \: \: solve \: \\ \\ (a \: + \: b) {}^{3} = {?} " alt=" \: \: solve \: \\ \\ (a \: + \: b) {}^{3} = {?} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
pshichka [43]3 years ago
6 0

Answer:

\huge\boxed{Answer\hookleftarrow}

(a + b) {}^{3}  \\  =  (a + b)  \times (a + b) {}^{2}  \\   = (a + b)(a {}^{2}  + 2ab + b {}^{2} ) \\  = a(a {}^{2}  + 2ab + b {}^{2} ) + b(a {}^{2}  + 2ab + b {}^{2} ) \\  = a {}^{3}  + 2a {}^{2} b + ab {}^{2}  + ba {}^{2} + 2ab {}^{2}  + b {}^{3}  \\  = a {}^{3}  + 3a {}^{2} b + 3ab {}^{2}  + b {}^{3}

✐<u> (a + b)³ = a³ + 3a²b + 3ab² + b³</u>

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# ꧁❣ RainbowSalt2²2² ࿐

Ivahew [28]3 years ago
5 0

Step-by-step explanation:

  • (a+b)³

=a³+3a²b+3ab²+b³

hope it is helpful to you

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3 years ago
During a mayoral election, candidate A spent $960,000 on her campaign, and candidate B spent
Thepotemich [5.8K]

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