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ryzh [129]
2 years ago
10

The Garzas have a kiddie pool and an adult swimming pool in their backyard. The kiddie pool is 7 feet long. The adult swimming p

ool is 42 feet long. How many times as long as the kiddie pool is the adult swimming pool?
Mathematics
1 answer:
Mandarinka [93]2 years ago
7 0

Given:

The kiddie pool is 7 feet long. The adult swimming pool is 42 feet long.

To find:

How many times as long as the kiddie pool is the adult swimming pool?

Solution:

Let adult swimming pool is x times the kiddie swimming pool.

42=x\times 7

42=7x

Divide both sides by 7.

\dfrac{42}{7}=\dfrac{7x}{7}

6=x

Therefore, adult swimming pool is 6 times the kiddie swimming pool.

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How to find the answers ?
maria [59]

AD || BC and BD is the transversal,

Therefore, angle DBC = angle ADB = 42° [alternate angles]

AD || BC and BD is the transversal,

angle BAD + angle ABD + angle DBC = 180° [co-interior angles]

or, 106°+ angle ABD + 42° = 180°

or, 148° + angle ABD = 180°

or, angle ABD = 180°-148° = 32°

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AB||CD and BC is the transversal,

angle ABC + angle BCD = 180° [co-interior angles]

or, 72+2x+12 = 180

or, 84+2x = 180

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b)42°

c)72°

3 0
2 years ago
The Lacrosse booster club is holding a raffle for a fundraiser. They will sell 100 tickets for $5 each and select 4 winners. All
Nadusha1986 [10]

Answer:

<h2>There are 3,921,225 ways to select the winners.</h2>

Step-by-step explanation:

This problem is about combinations with no repetitions, because the same person can't win four times. It's a combinaction because the order of winning doesn't really matter.

Combinations without repetitions are defined as

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Replacing values, we have

C_{100}^{4}  =\frac{100!}{4!(100-4)!}=\frac{100!}{4! 96!}=\frac{100 \times 99 \times 98 \times 97 \times 96!}{4! \times 96!}=  \frac{94,109,400}{24}= 3,921,225

Therefore, there are 3,921,225 ways to select the winners.

Additionally, as you can imagine, the probability of winning is extremely low, it would be 3,921,225 to 1.

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