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Mars2501 [29]
4 years ago
8

HELP ME PLEASE !!! I NEED IT

Mathematics
1 answer:
mihalych1998 [28]4 years ago
7 0

Answer:  [0, ∞)

<u>Step-by-step explanation:</u>

Since x² is positive, the parabola opens up (which means it has a minimum at the y-value of the vertex)

The y-value of the vertex is 0 -->  so the range is from 0 to positive infinity

In interval notation, it is written as [0, ∞)

<em>The bracket means 0 is included</em>

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\huge{ \fbox{ \sf{5b + 9}}}

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\star{ \text{( \: 3b + 5) + (2b + 4)}}

\text{Step \: 1 \:  :  \sf{Remove \: the \: unnecessary \: parentheses}}

\text{When \: there \: is \: a \: ( + ) \: in \: front \: of \: an \: expression \: in \: parentheses \:, there \: is \: no \: need \: to \: change \: the \: sign \: of \: each \: term \: in \: the \: expression.}

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\text{Step \: 2 \:  : Collect \: like \: terms.}

\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}

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\mapsto{ \sf{5b + 5 + 4}}

\text{ Step \: 3 \:  :  \sf{Add \: the \: numbers : 5 \: and \: 4}}

\mapsto{ \boxed {\sf{ {5b + 9}}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

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