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Makovka662 [10]
3 years ago
14

Are the two lines parallel, perpendicular, or neither?

Mathematics
1 answer:
RideAnS [48]3 years ago
5 0

Graph 1 neither

Graph 2 neither

Graph 3 perpendicular

Graph 4 parallel

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It takes Kay 20 minutes to drive to work traveiling 45 mph. Two minutes after she left home this morning, her husband, Dan, star
BARSIC [14]

Answer:

Kay's husband drove at a speed of 50 mph

Step-by-step explanation:

This is a problem of simple motion.

First of all we must calculate how far Kay traveled to her job, and then estimate the speed with which her husband traveled later.

d=vt

v=45 mph

t= 20 minutes/60 min/hour = 0.333 h (to be consistent with the units)

d= 45mph*0.333h= 15 miles

If Kay took 20 minutes to get to work and her husband left home two minutes after her and they both arrived at the same time, it means he took 18 minutes to travel the same distance.

To calculate the speed with which Kate's husband made the tour, we will use the same initial formula and isolate the value of "V"

d=vt; so

v=\frac{d}{t}

d= 15 miles

t= 18 minutes/60 min/hour = 0.30 h  (to be consistent with the units)

v=\frac{d}{t}=\frac{15 miles}{0.3 h}=50mph

Kay's husband drove at a speed of 50 mph

8 0
3 years ago
The new athletic facility on the downtown campus measures 0.74 km by 4 km. How many square
masha68 [24]

Answer:

The sports facility is 2,960,000 sq. m   in area.

Step-by-step explanation:

The dimension of the sport facility = 0.74 km by 4 km

The Length of the facility = 4 km

The width of the facility = 0.74 km

Now, 1 km = 1000 meters

⇒ 4 km = 4 x (1000) = 4000 meters

and 0.74 km = 0.74 x (1000) = 740 meters

Now, AREA OF THE RECTANGLE = LENGTH x WIDTH

So, the area of the facility = 4000 m  x 740 km

                                         =  2,960,000 sq. m

Hence, the sports facility is 2,960,000 sq. m  in area.

7 0
2 years ago
I'm rly bad at rotation so plz help!!!
cupoosta [38]
The answer is c cause it is the only one that rotated
5 0
3 years ago
Read 2 more answers
Find the distance between two points C(-6,5) and D(-3,1)
gladu [14]

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have:

C(-6,\ 5)\to x_1=-6,\ y_1=5\\D(-3,\ 1)\to x_2=-3,\ y_2=1

substitute:

d=\sqrt{(-3-(-6))^2+(1-5)^2}=\sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5

Answer: 5 units.

6 0
3 years ago
Is the answer: -5, -2, 3, 5?
lara31 [8.8K]

Answer:

Y= -1 and Y = -5

Step-by-step explanation:

To find the Value of Y need to find where the Line(s) Cross they Vertical Axis.

5 0
3 years ago
Read 2 more answers
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