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3 years ago

12

Help 5 points pls no wrong answer

1 answer:

grin007 [14]3 years ago

7 0

Answer:

A (3, 4) B (4, 2) C (0.5, 0.25) D (1, 2.5) E (1.75, 4.25)

Step-by-step explanation:

The coordinate points of a point are (x, y) where x is the number on the x-axis and y is the number on the y-axis.

By looking at points A and B they're easy to tell.

For points C, D, and E they're in between whole numbers so by converting the number given which is a fraction you can get 0.25 from 1/4 which is half of 1/2, 0.5 from 1/2, 0.75 from 3/4 which is half of 1/2 plus 1/2, 1.25 from 1 1/4, etc....

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(-3) x (-5) = ? please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

seropon [69]

The answers 15 because we have two negatives it's always a positive and 3×5 is 15

5 0

4 years ago

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The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Fin

NISA [10]

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, $\mu=8.04 g$

Standard deviation, $\sigma=0.08g$

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of machine components

$P(Xx_2)=0.03$

$P(X$

=0.03

From z- table we get

$P(Z1.88)=0.03$

Therefore, we get

$\frac{x_1-8.04}{0.08}=-1.88$

$x_1-8.04=-1.88\times 0.08$

$x_1=-1.88\times 0.08+8.04$

$x_1=7.8896$

$\frac{x_2-8.04}{0.08}=1.88$

$x_2=1.88\times 0.08+8.04$

$x_2=8.1904$

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

5 0

3 years ago

PLEASE HELP (80 points!!) <br> What if the following are equivalent to x^2/5 (more than once answer)

spin [16.1K]

Answer:

$\sqrt[5]{x^2}$ and $(\sqrt[5]{x} )^2$

Step-by-step explanation:

They are both correct.

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3 years ago

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You and a roommate are hosting a party. You invite 10 other pairs of roommates. During the party you poll everyone at the party

solong [7]

The orders of pairs are 23

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3 years ago

The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5

vladimir1956 [14]

Answer:

f=11

Mode=4

Median=4

Explanation:

We are given that

a.Mean of the exam score, $\bar x$ =3.5

Score(x) frequency C.F

1 1 1

2 3 4

3 f 15(4+f=4+11)

4 13 28

5 4 32

$\sum f_i=1+3+f+13+4=21+f$

$\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f$

$(\bar x)=\frac{\sum f_ix_i}{\sum f_i}$

Using the formula

$3.5=\frac{79+3f}{21+f}$

$73.5+3.5f=79+3f$

$3.5f-3f=79-73.5$

$0.5f=5.5$

$f=\frac{5.5}{0.5}=11$

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

$Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}$

Median= $\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4$

7 0

4 years ago