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Alex777 [14]
3 years ago
12

1.What is (f-g)(x) ? f(x)=x^4-3x^2+5x-7 g(x)= x^3-3x^2+3x-1

Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

that my answer

brainlist me

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A quadrilateral has angle measures of 102°, 84°, and 77°. What is the measure of the fourth angle?
Mashcka [7]

Answer:

Measure of the 4th angle = 360-(102+84+77)

= 360-263

= 97°

Hope this helps!

6 0
3 years ago
Help with this please.
spin [16.1K]
The answer would be because
7 0
3 years ago
The equation of line AG is y=_b_x. The midpoint of
Lina20 [59]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
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Please help!!!! Will mark brainliest!! 18 points.
andreyandreev [35.5K]

Method 1:

You can use the formula of an area of equilateral triangle:

A=\dfrac{a^2\sqrt3}{4}

a - length of side

We have a = 10 yd. Substitute:

A=\dfrac{10^2\sqrt3}{4}=\dfrac{100\sqrt3}{4}=25\sqrt3\ yd^2\\\\\sqrt3\approx1.7\\\\A=25(1.7)=\boxed{42.5\ yd^2}


Method 2:

Use the Pythagorean theorem (look at he picture).

5^2+h^2=10^2

25+h^2=100           <em>subtract 25 from both sides</em>

h^2=75\to h=\sqrt{75}\\\\h=\sqrt{25\cdot3}\\\\h=\sqrt{25}\cdot\sqrt3\\\\h=5\sqrt3\ yd

The formula of an area of a trinagle:

A=\dfrac{1}{2}bh

b - base

h - height

We have b = 10 yd and h = 5√3 yd. Substitute:

A=\dfrac{1}{2}(10)(5\sqrt3)=(5)(5\sqrt3)=25\sqrt3\ yd\\\\\sqrt3\approx1.7\\\\A=25(1.7)=\boxed{42.5\ yd^2}

8 0
3 years ago
Read 2 more answers
What is the mass of a copper (II) chloride sample if it contains 0.0344 moles of the compound?
ale4655 [162]

According to the valence number of copper(2+) and the same value for chlorine (1-) copper (II) chloride has the formula of CuCl2

The molar mass of copper is 0,0635 kg/mole and chlorine gas a molar mass of 0,035 kg/mole the compound will have a molar mass of ( 0,0635+2×0,035 )kg/mole=0,099kg/mole and 0,344 moles are equivalent in mass to 0,344×0,135 kg=0,046 kg

5 0
2 years ago
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