1.What is (f-g)(x) ?<br> f(x)=x^4-3x^2+5x-7<br> g(x)= x^3-3x^2+3x-1

Three of the four vertices of a rectangle are located at (4, 2), (7, 2) and (4, 8). a. What are the coordinates of the missing v

34kurt

Answer:

a) The coordinates of the missing vertex = (7, 8)

b) Area = 18 square units

Perimeter = 18 units

Step-by-step explanation:

a) We know three of the four vertices:

A: (4, 2) C ______ D(?)

B: (7, 2) | |

C: (4, 8) A |______| B

To find the coordinates of the missing vertex we need to calculate the distance in the x-direction from point A to point B:

$B_{x} - A_{x} = 7 - 4 = 3$

Hence, the distance of point D from point C in the x-direction is:

$D_{x} = C_{x} + 3 = 4 + 3 = 7$

Now, to find the coordinate in "y" we need to calculate the distance in the y-direction between point C and point A:

$C_{y} - A_{y} = 8 - 2 = 6$

Then, the distance of point D from point B in the y-direction is:

$D_{y} = B_{y} + 6 = 2 + 6 = 8$

Therefore, the coordinates of the missing vertex (point D) are:

$D = (D_{x}, D_{y}) = (7, 8)$

b) The area of the rectangle is:

$a = (B_{x} - A_{x})*(C_{y} - A_{y}) = 3*6 = 18 units^{2}$

The perimeter is given by:

$p = 2*(3 + 6) = 18 units$

I hope it helps you!

8 0

3 years ago

Choose the linear inequality that describes the graph. The gray area represents the shaded region.

jek_recluse [69]

Answer:

2x + 3y ≥ 5

Step-by-step explanation:

See the graph attached.

The bold straight line passes through the points (1,1) and (4,-1).

Therefore, the equation of the straight line will be

$\frac{y + 1}{- 1 - 1} = \frac{x - 4}{4 - 1}$

⇒ 3(y + 1) = - 2(x - 4)

⇒ 3y + 3 = - 2x + 8

⇒ 2x + 3y = 5 ............. (1)

Now, the shaded region i.e. the solution to the inequality does not include the origin(0,0).

So, putting x = 0 and y = 0 in the equation (1) we get, 0 < 5

Therefore, the inequality equation is 2x + 3y ≥ 5 (Answer)

6 0

3 years ago

CS Algebra

CaHeK987 [17]

Answer:

Hope this helps :)

Step-by-step explanation:

8(x - 2) = 2x + 8

y+9 = -2(y + 1)

value of x in 8(x - 2) = 2x + 8

x=4

substitue

y+9=−2(y+1)

value of y y+9=−2(y+1)

y= - 11/3 or 3.66...

x=4

y=4 (I rounded 3.66)

4 0

3 years ago

81.08% of 37 hours<br> (Answer in minutes please)

Fofino [41]

It would be: 37 × 0.8108 = 30 hours (approx.)

Now, we know, 1 hour = 60 min.
so, 30 hours = 60 × 30 = 1800 min.

In short, Your Answer would be 1800 min

Hope this helps!

6 0

4 years ago

Read 2 more answers

Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$

4 0

3 years ago

1.What is (f-g)(x) ? f(x)=x^4-3x^2+5x-7 g(x)= x^3-3x^2+3x-1