Answer:
Catherine is not correct (see the explanation)
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The formula to calculate the slope between two points is equal to
the two points from the graph are
(4,40) and (7,70)
substitute the values in the formula
therefore
Catherine is not correct
Your factoring answer is: (x^2+25)(x+5)(x-5)
Answer:
6 2/3 minutes
Step-by-step explanation:
3 hours on frames 3 x 60 = 180 minutes total
180/27 frames = 6.66667 or 6 2/3 minutes.
Answer:
![\sqrt[n]{x}=x^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Step-by-step explanation:
The index of a radical is the denominator of a fractional exponent, and vice versa. If you think about the rules of exponents, you know this must be so.
For example, consider the cube root:
![\sqrt[3]{x}\cdot \sqrt[3]{x}\cdot \sqrt[3]{x}=(\sqrt[3]{x})^3=x\\\\(x^{\frac{1}{3}})^3=x^{\frac{3}{3}}=x^1=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%20%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%20%5Csqrt%5B3%5D%7Bx%7D%3D%28%5Csqrt%5B3%5D%7Bx%7D%29%5E3%3Dx%5C%5C%5C%5C%28x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3Dx%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D%3Dx%5E1%3Dx)
That is ...
![\sqrt[3]{x}=x^{\frac{1}{3}} \quad\text{radical index = fraction denominator}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%5Cquad%5Ctext%7Bradical%20index%20%3D%20fraction%20denominator%7D)
Answer:
1) ∠A=84°
2) ∠C=20°
Step-by-step explanation:
1)
First, find ∠C:
<em>(I'm assuming the exterior angle of 126° makes a straight line with ∠C)</em>
The angles on a straight line always add up to 180. Therefore:
∠C+126=180
∠C=180-126
∠C=54
Then find ∠B:
We also know that all the angles in a triangle add up to 180. Therefore:
∠A+∠B+∠C=180
∠A+∠B+54=180
∠A+∠B=126
<em>(we know ∠A=2(∠B))</em>
2(∠B)+∠B=126
3(∠B)=126
∠B=42
Now, find ∠A:
∠A=2(∠B)
∠A=2(42)
∠A=84°
2)
First, find ∠B:
<em>(Again, I'm assuming the exterior angle of 100° makes a straight line with ∠B)</em>
The angles on a straight line always add up to 180. Therefore:
∠B+100=180
∠B=180-100
∠B=80
Then find ∠A:
We also know that all the angles in a triangle add up to 180. Therefore:
∠A+∠B+∠C=180
∠A+80+∠C=180
∠A+∠C=100
<em>(we know ∠A=4(∠C))</em>
4(∠C)+∠C=100
5(∠C)=100
∠C=20°
