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3 years ago

The list below shows the heights in meters,of five different buildings.

Mathematics

2 answers:

wariber [46]3 years ago

3 0

162m is the answer. Just add 'em all and divide how many numbers there are.

marusya05 [52]3 years ago

3 0

The correct answer is

160

Median = The number in the middle.

Glad I could help, and good luck!

AnonymousGiantsFan

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6. Using the discriminant, determine the value of k that will give 1 solution (i.e. discriminant equals zero) y = kx²-4x + 4

Gwar [14]

Answer:

k = 1

Step-by-step explanation:

<u>Discriminant</u>

$b^2-4ac\quad\textsf{when }\:ax^2+bx+c=0$

$\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}$

$\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}$

$\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}$

As we need to determine the value of k that will give <u>one solution</u>, set the <u>discriminant to zero</u>.

<u>Given equation</u>:

$y=kx^2-4x+4$

Therefore:

a = k
b = -4
c = 4

Substitute these values into the discriminant and solve for k:

$\begin{aligned}b^2-4ac & = 0\\\implies (-4)^2-4(k)(4) & = 0\\16-16k & = 0\\16k & = 16\\\implies k & = 1\end{aligned}$

4 0

2 years ago

4. The cube root parent function is vertically stretched by a factor of 3, reflected in the x-axis,

Mademuasel [1]

Using translation concepts, it is found that the equation that represents the new function is:

$y = -3\sqrt[3]{x} - 8$

The cube root parent function is given by:

$y = \sqrt[3]{x}$

<h3>Translation:</h3>

The function goes through these following translations:

Vertically stretched by a factor of 3, that is, it is multiplied by 3, hence $y = 3\sqrt[3]{x}$ .

Reflected over the x-axis, that is, it is multiplied by -1, hence $y = -3\sqrt[3]{x}$ .

Translated 8 units down, that is, 8 is subtracted from the function, hence $y = -3\sqrt[3]{x} - 8$ .

Then, the equation is:

$y = -3\sqrt[3]{x} - 8$

To learn more about translation concepts, you can take a look at brainly.com/question/13671886

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Alexxx [7]

Answer:

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Step-by-step explanation:

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AlekseyPX

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