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WINSTONCH [101]
1 year ago
11

6. Using the discriminant, determine the value of k that will give 1 solution (i.e. discriminant equals zero) y = kx²-4x + 4 ​

Mathematics
1 answer:
Gwar [14]1 year ago
4 0

Answer:

k = 1

Step-by-step explanation:

<u>Discriminant</u>

b^2-4ac\quad\textsf{when }\:ax^2+bx+c=0

\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}

\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}

\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}

As we need to determine the value of k that will give <u>one solution</u>, set the <u>discriminant to zero</u>.

<u>Given equation</u>:

y=kx^2-4x+4

Therefore:

  • a = k
  • b = -4
  • c = 4

Substitute these values into the discriminant and solve for k:

\begin{aligned}b^2-4ac & = 0\\\implies (-4)^2-4(k)(4) & = 0\\16-16k & = 0\\16k & = 16\\\implies k & = 1\end{aligned}

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