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2 years ago

Compare and contrast autotrophs and heterotrophs

Biology

1 answer:

emmasim [6.3K]2 years ago

6 0

Answer:

Autotrophs are organisms that can produce their own food from the substances available in their surroundings using light (photosynthesis) or chemical energy (chemosynthesis). Heterotrophs cannot synthesize their own food and rely on other organisms — both plants and animals — for nutrition.

autotrophs are known are known as producers because they are able to make their own food from raw materials and energy, such as plants, algae and some types of bacteria.

heterotrophs are known as consumers Because they consume producers or other consumers such as dogs, birds, fish and humans.

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Which of the following most accurately describes a pasture?

kolezko [41]

The answer is either -unfenced land where grass or grass-like vegetation grows and is the dominant form of plant life, or -an enclosed field covered with grass or similar plant and suitable for grazing by livestock.
I am not sure which though.
I hope this helps you!
Have a nice day! :)

3 0

3 years ago

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In a population of plants, the allele for long stems (S) is completely dominant over the allele for short stems (s). If 35% of t

Sergio [31]

Answer:

The correct answer would be 48 percent.

It can be solved by using the Hardy-Weinberg equation.

p² + 2pq+ q² = 1

p + q = 1

where, p² represents homozygous dominant's frequency that is, SS in this case,

q² represents homozygous recessive's frequency that is, ss in this case,

2pq represents heterozygous dominant's frequency that is, Ss in this case.

p represents dominant allele's frequency and q represents the recessive allele's frequency.

Now, the percentage of homozygous recessive or short stems is 35%. Therefore, the frequency of homozygous recessive would be 0.35.

Thus, the value of q² = 0.35

So, q = $\sqrt{0.35}$ = 0.59 which is approximately equals to 0.6.

As p + q = 1 so, q = 1 - 0.6 = 0.4

The frequency of heterozygous (Ss) = 2pq = 2(0.6)(0.4) = 0.48

Hence, the frequency of heterozygous would be 48 percent.

8 0

3 years ago

Which of these is accomplished by the interaction of haploid cells in sexually reproducing organisms? A. deletion of genetic mat

Licemer1 [7]

The right answer is D.

A gamete is a generally haploid reproductive cell specialized in fertilization, or gamy (that is to say, able to fuse with another gamete, complementary type if necessary), in eukaryotes.

The process that carries out the fusion of two gametes is called fertilization or gamy, it is the complementary event of meiosis. Fertilization produces a new single cell, called a zygote, whose chromosome number has doubled to 2n.

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3 years ago

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Which of the following was the most likely effect of the Industrial Revolution on peppered moths in cities?

jeka57 [31]

The answer is d. The population of light-colored moths decreased and the population of dark-colored moths increased.

Peppered moth color variation is a good example of natural selection. During the Industrial revolution, due to pollution, trees become darker in the urban area. Light-colored moths were, thus, easy prey. The dark-colored moths were able to camouflage on dark trees and avoid predators. The phenomenon is known as industrial melanism. So, in polluted urban areas, the number of dark-colored peppered moths increased. In the clean environment, were much effective in hiding from predators and they outnumbered the dark-colored moths.

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3 years ago

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Refer to Animation: Countercurrent Multiplication. What would you predict to be the effect on an animal species of having longer

attashe74 [19]

Answer:

The correct answers is: I would predict that animals with longer loops of Henle would be able to concentrate their urine more than animals with shorter loops, and thus they would more likely survive in desserts and other dry areas.

Explanation:

The Loop of Henle is a tubule system that connects the proximal convoluted tubule to the distal convoluted tubule in a nephron, the functional and structural unit of the kidney. Its primary job is to establish a concentration gradient in the kidney's medulla by creating a high urea concentration deep in the medulla using a countercurrent multiplier system that uses electrolyte pumps. Through this mechanism, water is reabsorbed to concentrate the urine and impede dehydration.

The length of the loops of Henle is of great importance for the countercurrent multiplier system - the longer they are, the more concentrated the urine can get. Therefore, animals with longer loops can survive better in habitats where there is not much water around.

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3 years ago