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iVinArrow [24]
3 years ago
15

Which expression is equivalent to ^3 square root 343 x^9 v^12 z^6?

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

\sqrt[3]{343x^9v^{12}z^6}=\sqrt[3]{343}\cdot\sqrt[3]{x^{3\cdot3}}\cdot\sqrt[3]{v^{4\cdot3}}\cdot\sqrt[3]{z^{2\cdot3}}\\\\=\sqrt[3]{7^3}\cdot\sqrt[3]{(x^3)^3}\cdot\sqrt[3]{(v^4)^3}\cdot\sqrt[3]{(z^2)^3}=7x^3v^4z^2\\\\Used:\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\(a^n)^m=a^{nm}\\\\\sqrt[n]{a^n}=a

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-x - 4 = 4x - 54 im to lazy to figure it out myself
BlackZzzverrR [31]

Step-by-step explanation:

  • <em>-x-4=</em><em>4</em><em>x</em><em>-</em><em>5</em><em>4</em>

Adding x on both sides, we get

  • <em>-x-4+</em><em>x=</em><em>4</em><em>x</em><em>-</em><em>5</em><em>4</em><em>+</em><em>x</em>
  • <em>-</em><em>4</em><em>=</em><em>5</em><em>x</em><em>-</em><em>5</em><em>4</em>

Adding 54 on both sides, we get

  • <em>-</em><em>4</em><em>+</em><em>5</em><em>4</em><em>=</em><em>5</em><em>x</em><em>-</em><em>5</em><em>4</em><em>+</em><em>5</em><em>4</em>
  • <em>5</em><em>0</em><em>=</em><em>5</em><em>x</em>

Dividing both sides by 5, we get

  • <em>5</em><em>0</em><em>/</em><em>5</em><em>=</em><em>5</em><em>x</em><em>/</em><em>5</em>
  • <em>1</em><em>0</em><em>=</em><em>x</em>

<em>Hence,</em><em> </em><em>the </em><em>value</em><em> of</em><em> x</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em>.</em>

5 0
2 years ago
-x + 3 = 2 ( x + 15 )
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Answer:

x= -9

Step-by-step explanation:

-x+3=2(x+15)

-x+3=2x+30

-x-2x+3=30-3

-3x=30-3

-3x=27

x= -9

3 0
3 years ago
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3/4=0.75 or 75%
1/2=0.5 or 50%

So, 3/4 is bigger.
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