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ss7ja [257]
2 years ago
5

express 0.016 as fraction in the lowest term podcast will mark as brainlist and will like and will rate u​

Mathematics
1 answer:
maxonik [38]2 years ago
7 0
The lowest term of 0.016 as a fraction is 2/125
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1. The following diagram shows part of the graph of y=p⋅sin(qx)+r. The point A (15, 2) is a maximum point and B(45, 1) is a mini
siniylev [52]

Answer: y = (1/2)*sin(x*pi/30) + 3/2

Step-by-step explanation:

We have the equation:

y = p*sin(q*x) + r.

in this case, p is the amplitude, which is calculated as half of the difference between the value at the peak (the maximum) and the value at the troughs (the minimums).

q is related to the period

r is the mid value of the function, will be equal to the minimum plus the amplitude (or the maximum minus the amplitude).

We know that the maximum is (15, 2) (x = 15, y = 2)

We know that the minimum is (45, 1) (x = 45, y = 1)

Then the value of y at the peak is 2, and the value of y at the trough is 1.

This means that the amplitude is:

p = (2 - 1)/2 = (1/2)

And we know that r is equal to the minimum plus one time the amplitude, then:

r = 1 + 1/2 = 3/2.

Then, for now, our equation is:

y = (1/2)*sin(q*x) + 3/2.

Now we can use the information that  (15, 2) is a maximum.

We know that the maximum value of the function sin(x) is 1.

and it is when:

x = (pi/2) + n*2*pi   (where n is a whole number)

Then we must have that:

15*q = (pi/2) + n*2*pi

as this is periodic, we can define n = 0 and it will be the same.

15*q = pi/2

q = (pi/2)/15 = pi/30.

Now, let's test this with the minimum.

The minimum of the sin(x) function is when:

x = (3/2)*pi + k*2*pi (where k can be any whole number)

and we have a minimum at x = 45, then:

q*45 = (3/2)*pi + k*2*pi

(pi/30)*45 = (3/2)*pi + k*2*pi

(45/30) = (3/2) + k*2

3/2 = 3/2 + k*2

If we take k = 0, then the equality is true

Then q  = pi/30 is consistent.

So we can conclude that the equation is:

y = (1/2)*sin(x*pi/30) + 3/2

5 0
3 years ago
Help a fella out Y'all. please n thank you
Virty [35]
Alrighty mate.

I reckon the answer as hmmm...I'd say<u><em> D</em></u>. All ya gotta do is just cover up the opposite variable and solve for the intercept yar lookin' for. 

I hope I helped mate.
3 0
3 years ago
Rewrite the expression as a sum of terms, where each term is in the form k\cdot a^nk⋅a
muminat

Answer:

  2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}

Step-by-step explanation:

It looks like you want to expand the expression ...

  \sqrt{a}\left(2a^2 -\dfrac{4}{a}\right)

Use the distributive property and rules of exponents.

  =2a^{(\frac{1}{2}+2)}-4a^{(\frac{1}{2}-1)}\\\\=\boxed{2a^{\frac{5}{2}}-4a^{-\frac{1}{2}}}

_____

The relevant rules of exponents are ...

  √a = a^(1/2)

  1/a = a^-1

  (a^b)(a^c) = a^(b+c)

8 0
3 years ago
Find the angle to the nearest degree. *<br> sin-10.5166<br> 1<br> 31.1°<br> 58.9°<br> 0.5°
Mice21 [21]

Given:

The given inverse trigonometric term is:

\sin^{-1}(0.5166)

To find:

The value given inverse trigonometric term.

Solution:

We have,

\sin^{-1}(0.5166)

Using the calculator, we get

\sin^{-1}(0.5166)=31.10446

\sin^{-1}(0.5166)\approx 31.1^{\circ}

The value of given term is 31.1°.

Therefore, the correct option is B.

6 0
2 years ago
A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If
lbvjy [14]

Answer:

2ft

Step-by-step explanation:

5 x 10=50

7 x 12= 84

5+2=7 and 10+2=12

3 0
3 years ago
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