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alina1380 [7]
3 years ago
12

Which is a correct step in solving the following equation for g?

Mathematics
1 answer:
OleMash [197]3 years ago
8 0
1. -2g = 1.75 -4
-g = -2.25/2
g = 1.12
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A circle has a diameter of 24 ft. What is its circumference?
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The circumference would be 12*3.14/2=18.84

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The radius of a basketball is 4.7 inches.what the volume of the basketball? Round to the nearest 10
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The formula for the volume of a sphere is V= \frac{4}{3}  \pi r^3. Plugging in 4.7 for your radius, we get V= \frac{4}{3} \pi 4.7^2= \frac{4}{3} \pi 22.09= \frac{88.36}{3} \pi, which is roughly 29.453π≈92.530.
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A circle has a circumfernce of 6. It has an arc length of 1
fomenos

Answer:

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6= πd and then divide both sides of the equation by π you get that d = 1.90

To find the central angle of an arc you would use the equation S = rθ where S is the length of the arc, r is the radius of the circle, and θ is the measure of the angle which in this case is unknown. So with S = 1 and r = d/2 = 1.90/2 = 0.9549 you would have an equation that looks like this:

1 = 0.9549θ.  

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8 0
3 years ago
Each pound of food C contains 6 ounces of ingredient P and 3 ounces of ingredient Q. Each pound of food D contains 4.5 ounces of
GuDViN [60]
So hmm the food C = 6p + 3q  and the food D = 4.5p + 1.5q

now, if we check how much is the ratios of C/D for each component, then, mixture M = 144p + 60q, must contain the same ratio for each "p" and "q" component

\bf \textit{ratio of "p"}\implies \cfrac{6}{4.5}\implies \cfrac{4}{3}
\\\\\\
\textit{ratio of "q"}\implies \cfrac{3}{1.5}\implies \cfrac{2}{1}

so, if we divide the 144p by 4+3, or 7 even pieces, 4 must belong to food C and 3 to food D, retaining the ratio of 4/3

and we do the same for 60q, we divide it in 2+1 or 3 even pieces, but that one is very clear, 2 must belong to food C and 1 to food D, 60/3 is clear ends up with a ratio of 40 and 20

now the "p" part... ends up as \bf \cfrac{144}{7}\cdot 4\qquad and\qquad \cfrac{144}{7}\cdot 3\implies \cfrac{576}{7}\qquad and\qquad \cfrac{432}{7}

that's what I see it, as the ratio of 4/3 and 2/1 being retained in the mixture M
7 0
3 years ago
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