Brianna has 3 posters she wants to hang on the wall. How many different ways can

A company produces metal slabs for industrial use. The slabs come in three thicknesses: 5in, 10in., 15 in. The weights of each t

Dimas [21]

5, 10 ,15

divide each by 5

1,2, 3

so the ratios should be 1,2,3

Metal 1 : divide by 150

1,2,4

Metal 2 divide by 130

1,2,3

Metal 3 divide by 310

1,2,3

Metal 4 divide by 140

1,2,3

Metal 1 is not proportional

Choice A

4 0

3 years ago

Help asap!! interpret the meaning of the expression

Triss [41]

Answer:

D

Step-by-step explanation:

This is exponential growth, and to my understanding, the format goes:

initial amount (percent growth/ decay)^time

percent growth = (decimal percent + 1)

percent decay = (1 - decimal percent)

Your equation:

1500(1.02)^t

Using the above format, 1500 appears to be the initial amount, which increases by 2% per annum.

i think

4 0

3 years ago

Read 2 more answers

Easy Points! Let f(x) represent a function. Which descriptions match the given transformations? Drag and drop the answers into t

Molodets [167]

F(x)-4 : translated 4 units down
4f(x) : vertical stretched by a factor of 4

4 0

3 years ago

Which postulate or theorem proves that △QRS and △TRS are congruent?

Vanyuwa [196]

Answer:

Option D is correct.

SAS Congruence Postulates

Step-by-step explanation:

In Δ QRS and Δ TRS

$QS \cong ST$ [Side] [Given]

$RS \cong RS$ [Common Side] [Given]

$\angle RSQ \cong \angle RST = 90^{\circ}$ [Angle]

SAS(Side- Angle -Side) postulates states states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.

Then, by SAS postulates

$\triangle QRS \cong \triangle TRS$

8 0

2 years ago

Suppose that 15% of people dont show up for a flight, and suppose that their decisions are independent. how many tickets can you

geniusboy [140]

Answer: 157 tickets

Explanation:

The people not showing up for the flight can be treated as from Binomial distribution.

The binomial distribution B(n, p) is approximately close to the normal i.e. N(np, np(1 − p)) for large 'n' and for 'p' and neither too close to 0 nor 1 .

Now, Let us assume 'n' = n

and we are given

p=0.15

So now B(n,0.15n) follows Normal distribution

u=n

$\sigma^{2}$ = 0.15n

We have to calculate P(X<144) with 99% accuracy

P(X<144) = P(Z<z)

where;

z= $(144-\bar{X})\div \sigma$

z score for 99% is 2.33

i.e.

$(144-\bar{X})\div \sigma = (144-n)/\sqrt{np} = 2.33\\\ (144-n)^{2} = \ np*2.33^{2}\\\ 20736 +n^{2} - 288n = 0.15n*5.43\\\ n^{2} - 288.81n + 20736=0$

solving this we will get one root nearly equal to 157 and other root as 133

Hence the answer is 157.

8 0

2 years ago