Given Information:
Total cards = 108
Red cards = 25
yellow cards = 25
Blue cards = 25
Green cards = 25
Wild cards = 8
Required Information:
Probability that a hand will contain exactly two wild cards in a seven-hand game = ?
Answer:
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
Step-by-step explanation:
The required probability is given by
P = number of ways of interest/total number of ways
The total number of ways of dealing a seven-card hand is
₁₀₈C₇
We want to select exactly 2 wild cards and the total wild cards are 8 so the number of ways of this selection is
₈C₂
Since the game is seven-card hand, we have to get the number of ways to select remaining 5 cards out of (108 - 8 = 100) cards.
₁₀₀C₅
Therefore, the setup for this problem becomes
P = number of ways of interest/total number of ways
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
This is the required setup that we can type into our calculators to get the probability of exactly two wild cards in a seven-hand card game with 8 wild cards and 108 total cards.
Answer:
4) 7,24,27
Step-by-step explanation:
My answer is should: increase of 4.5
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P.S..If you have options then it's better................
Hello There!
<h2>
EQUATION 15+M=35</h2><h2>
</h2><h2>M = 20 MILES</h2>
Answer:
22,000
Step-by-step explanation:
4%/100=0.04
0.04*50,000=20,000 || 130,000-50,000=80,000 ||
2%/100=0.02
0.02*100,000= 2,000 || 80,000 - 100,000 ||
To explain it simply, Rosie receives 20,000 in commission for the first 50,000 of the sale. However, she sold a property for 130,000 meaning she also receives 2,000 for the next 100,000. Therefore she receives $22,000 in total on her $130,000 sale.
