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Zarrin [17]
2 years ago
5

Please help question in the picture

Mathematics
1 answer:
tigry1 [53]2 years ago
8 0
There really isn’t a possible answer since there is not enough information given. Not from what I have learned so far at least, but using common sense, and the process of elimination I would say 30
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Three forces of 300 N in the direction of N30E, 400N in the direction of N60E and
andreyandreev [35.5K]

Split up each force into horizontal and vertical components.

• 300 N at N30°E :

(300 N) (cos(30°) i + sin(30°) j)

• 400 N at N60°E :

(400 N) (cos(60°) i + sin(60°) j)

• 500 N at N80°E :

(500 N) (cos(80°) i + sin(80°) j)

The resultant force is the sum of these forces,

∑ F = (300 cos(30°) + 400 cos(60°) + 500 cos(80°)) i

… … …  + (300 sin(30°) + 400 sin(60°) + 500 sin(80°)) j N

∑ F ≈ (546.632 i + 988.814 j) N

so ∑ F has a magnitude of approximately 1129.85 N and points in the direction of approximately N61.0655°E.

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2 years ago
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Step-by-step explanation:

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jeka94

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Step-by-step explanation:

The patterns are shapes

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3 years ago
Please answer this correctly
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Answer: 1/4

Step-by-step explanation:

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saveliy_v [14]

Answer:140ft2

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