<u>Options</u>
![(A)\left(-\infty , \dfrac23\right]\\\\(B)\left(-\infty , \dfrac23\right) \\\\(C)(\frac23\right, \infty ) \\\\(D) [\frac23\right, \infty )](https://tex.z-dn.net/?f=%28A%29%5Cleft%28-%5Cinfty%20%2C%20%5Cdfrac23%5Cright%5D%5C%5C%5C%5C%28B%29%5Cleft%28-%5Cinfty%20%2C%20%5Cdfrac23%5Cright%29%20%5C%5C%5C%5C%28C%29%28%5Cfrac23%5Cright%2C%20%5Cinfty%20%29%20%5C%5C%5C%5C%28D%29%20%5B%5Cfrac23%5Cright%2C%20%5Cinfty%20%29)
Answer:
Step-by-step explanation:
Given the solution to an inequality
{x|x>2/3}
The solution set does not include 
, therefore, it must be open at the left. Recall that we use a curvy bracket ( to denote openness at the left.
Since x is greater than , the solution set contains all values of larger than up till infinity. Since infinity is an arbitrarily large value, we also use an open bracket at the right.
Therefore, another way to represent the solution {x|x>2/3} is:
The correct option is C.
Capacity=L^3
=8×8×8
=512L
Answer:
x= -5/3
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
7(5x+9)=12−(x+9)
7(5x+9)=12+−1(x+9)(Distribute the Negative Sign)
7(5x+9)=12+−1x+(−1)(9)
7(5x+9)=12+−x+−9
(7)(5x)+(7)(9)=12+−x+−9(Distribute)
35x+63=12+−x+−9
35x+63=(−x)+(12+−9)(Combine Like Terms)
35x+63=−x+3
35x+63=−x+3
Step 2: Add x to both sides.
35x+63+x=−x+3+x
36x+63=3
Step 3: Subtract 63 from both sides.
36x+63−63=3−63
36x=−60
Step 4: Divide both sides by 36.
36x/36 and -60/36
x= -5/3
Answer:
5
Step-by-step explanation:
-5 + 5 = 0
