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3 years ago

What number had an experimental probability that matched its theoretical probability

Mathematics

1 answer:

noname [10]3 years ago

7 0

Answer:

here

https://decabonner.weebly.com/uploads/1/6/4/8/1648294/day_1_-_practice_wksht_-_basic_probability_key.pdf

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9. Find the Highest Common Factor of

netineya [11]

C. 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60

1,000: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

Now we find the common numbers. One doesn’t count as when multiplied later on, it will not change anything.

60: 2, 4, 5, 10, 20

1,000: 2, 4, 5, 10, 20

The highest common factor is 20 because it’s, well, the highest number.

D. Do the same thing for D.

24: 1, 2, 3, 4, 6, 8, 12, 24

880: 1, 2, 4, 5, 8, 10, 11, 16, 20, 22, 40, 44, 55, 80, 88, 110, 176, 220, 440, 880

20 and 880: 2, 4, 8

8 is the Highest Common Factor.

E. Do the same thing with E.

90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

1,000: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

90 and 1000: 2, 5, 10

10 is the Highest Common Factor.

3 0

3 years ago

Read 2 more answers

Help Fast

horrorfan [7]

Answer:

6 square root of 2

Step-by-step explanation:

sin theta = opposite / hypotenuse

sin 45 = 6/x

Multiply by x

x sin 45 = 6

Divide by sin 45

x sin 45/ sin 45 = 6 / sin 45

x = 6/ sin 45

x = 6/ (1/sqrt(2))

x = 6 sqrt(2)

3 0

3 years ago

Read 2 more answers

½x + 1 ⅔ subtracted from 1 ½x - 1 ⅓<br> simplify IF NEEDED

Volgvan

Answer:

$( \frac{1}{2} x + 1 \frac{2}{3} ) - (1 \frac{1}{2} x - 1 \frac{1}{3} ) \\ = ( \frac{1}{2} - \frac{3}{2} )x + ( \frac{5}{3} + \frac{4}{3} ) \\ = \frac{ - 2}{2} x + \frac{9}{3} \\ = - x + 3 \\ = 3 - x$

4 0

4 years ago

Which of the following expressions is equivalent to a3 + b3?

lubasha [3.4K]

ANSWER
${a}^{3} + {b}^{3} = (a + b)( {a}^{2 } - ab + {b}^{2} )$

EXPLANATION

To find the expression that is equivalent to
${a}^{3} + {b}^{3}$
we must first expand
${(a + b)}^{3}$
Then we rearrange to find the required expression.

So let's get started.

${(a + b)}^{3} = (a + b) {(a + b)}^{2}$

We expand the parenthesis on the right hand side to get,

${(a + b)}^{3} = (a + b) ( {a}^{2} + 2ab + {b}^{2} )$

We expand again to obtain,

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Let us group the cubed terms on the right hand side to get,

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3 {a}^{2}b + 3a {b}^{2}$

${(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab (a+ b)$

We make the cubed terms the subject,

${(a + b)}^{3} - 3ab (a+ b) = {a}^{3} + {b}^{3}$

We factor to get,

$(a + b)({(a + b)}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We expand the bracket on the left hand side to get,

$(a + b)( {a}^{2} + 2ab + {b}^{2} - 3ab ) = {a}^{3} + {b}^{3}$

We finally simplify to get,

$(a + b)( {a}^{2} - ab + {b}^{2} ) = {a}^{3} + {b}^{3}$

5 0

3 years ago

Read 2 more answers

408 rounded to the nearest tenth

andreev551 [17]

408 round to the nearest tenth: 410

3 0

3 years ago