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allochka39001 [22]
3 years ago
7

What number had an experimental probability that matched its theoretical probability

Mathematics
1 answer:
noname [10]3 years ago
7 0

Answer:

here

https://decabonner.weebly.com/uploads/1/6/4/8/1648294/day_1_-_practice_wksht_-_basic_probability_key.pdf

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9. Find the Highest Common Factor of
netineya [11]
C. 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60

1,000: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

Now we find the common numbers. One doesn’t count as when multiplied later on, it will not change anything.

60: 2, 4, 5, 10, 20

1,000: 2, 4, 5, 10, 20

The highest common factor is 20 because it’s, well, the highest number.

D. Do the same thing for D.

24: 1, 2, 3, 4, 6, 8, 12, 24

880: 1, 2, 4, 5, 8, 10, 11, 16, 20, 22, 40, 44, 55, 80, 88, 110, 176, 220, 440, 880

20 and 880: 2, 4, 8

8 is the Highest Common Factor.

E. Do the same thing with E.

90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

1,000: 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000

90 and 1000: 2, 5, 10

10 is the Highest Common Factor.

3 0
3 years ago
Read 2 more answers
Help Fast
horrorfan [7]

Answer:

6 square root of 2

Step-by-step explanation:

sin theta = opposite / hypotenuse

sin 45 = 6/x

Multiply by x

x sin 45 = 6

Divide by sin 45

x sin 45/ sin 45 = 6 / sin 45

x = 6/ sin 45

x = 6/ (1/sqrt(2))

x = 6 sqrt(2)

3 0
3 years ago
Read 2 more answers
½x + 1 ⅔ subtracted from 1 ½x - 1 ⅓<br> simplify IF NEEDED
Volgvan

Answer:

( \frac{1}{2} x + 1 \frac{2}{3} ) - (1 \frac{1}{2} x - 1 \frac{1}{3} ) \\  = ( \frac{1}{2}  -  \frac{3}{2} )x  +  ( \frac{5}{3}  +  \frac{4}{3} ) \\  =  \frac{ - 2}{2} x +  \frac{9}{3}  \\  =  - x + 3 \\  = 3 - x

4 0
4 years ago
Which of the following expressions is equivalent to a3 + b3?
lubasha [3.4K]
ANSWER
{a}^{3}  + {b}^{3} = (a + b)( {a}^{2 }  - ab +  {b}^{2} )


EXPLANATION

To find the expression that is equivalent to
{a}^{3}  + {b}^{3}
we must first expand
{(a + b)}^{3}
Then we rearrange to find the required expression.


So let's get started.


{(a + b)}^{3}  = (a + b) {(a + b)}^{2}

We expand the parenthesis on the right hand side to get,



{(a + b)}^{3}  = (a + b) ( {a}^{2} + 2ab +  {b}^{2}  )



We expand again to obtain,

{(a + b)}^{3}  =  {a}^{3}  + 3 {a}^{2}b + 3a {b}^{2}   +  {b}^{3}


Let us group the cubed terms on the right hand side to get,

{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3 {a}^{2}b + 3a {b}^{2}




{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3ab (a+ b)





We make the cubed terms the subject,

{(a + b)}^{3}  - 3ab (a+ b) =  {a}^{3}   +  {b}^{3}

We factor to get,


(a + b)({(a + b)}^{2}  - 3ab ) =  {a}^{3}   +  {b}^{3}


We expand the bracket on the left hand side to get,

(a + b)( {a}^{2}  + 2ab +  {b}^{2}   - 3ab ) =  {a}^{3}   +  {b}^{3}


We finally simplify to get,

(a + b)( {a}^{2}   - ab +  {b}^{2}  ) =  {a}^{3}   +  {b}^{3}
5 0
3 years ago
Read 2 more answers
408 rounded to the nearest tenth
andreev551 [17]
408 round to the nearest tenth: 410
3 0
3 years ago
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