A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms
Balls height 
To find all values of t for which the ball's height is 3 meters
We plug in 3 for h and solve for t
Solve for t
Solve using quadratic formula
After simplifying this,
= 0.11898
= 1.68102
the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec
Answer:
=25x-7
Step-by-step explanation:
F(X)= x+1/4x-2
f(2) = (2 + 1)/[(4)(2) - 2]
f(2) = 3/6 = 1/2
Answer:
slaves
Step-by-step explanation:
Answer:
We can have two cases.
A quadratic function where the leading coefficient is larger than zero, in this case the arms of the graph will open up, and it will continue forever, so the maximum in this case is infinite.
A quadratic function where the leading coefficient is negative. In this case the arms of the graph will open down, then the maximum of the quadratic function coincides with the vertex of the function.
Where for a generic function:
y(x) = a*x^2 + b*x + c
The vertex is at:
x = -a/2b
and the maximum value is:
y(-a/2b)
