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3 years ago

Compare 5/12 and 4/6

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

5 0

5/12 is your answer

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Select the best possible first step to solving the system by first eliminating the x variable. 3x − 9y = 6 2x − 11y = 6

Klio2033 [76]

The first step would be to add 3x and 2x i believe but I am not sure

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3 years ago

Divide. (3 3/4)÷(−2 1/2) Enter your answer as a mixed number, in simplified form, in the box.

neonofarm [45]

$3 \frac{3}{4} = \frac{15}{4}$

Because (4*3) + 3 = 15. Similary find the improper fraction for -2 1/2.

(15/4) / (-5/2) = -3/2

Convert -3/2 into a mixed fraction.

Therefore, -3/2 = -1 1/2.

6 0

3 years ago

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Find the solution of the problem (1 3. (2 cos x - y sin x)dx + (cos x + sin y)dy=0.

lakkis [162]

Answer:

$2*sin(x)+y*cos(x)-cos(y)=C_1$

Step-by-step explanation:

Let:

$P(x,y)=2*cos(x)-y*sin(x)$

$Q(x,y)=cos(x)+sin(y)$

This is an exact differential equation because:

$\frac{\partial P(x,y)}{\partial y} =-sin(x)$

$\frac{\partial Q(x,y)}{\partial x}=-sin(x)$

With this in mind let's define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x}=P(x,y)$

and

$\frac{\partial f(x,y)}{\partial y}=Q(x,y)$

So, the solution will be given by f(x,y)=C1, C1=arbitrary constant

Now, integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y)

$f(x,y)=\int\ 2*cos(x)-y*sin(x)\, dx =2*sin(x)+y*cos(x)+g(y)$

where g(y) is an arbitrary function of y

Let's differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y}=\frac{\partial }{\partial y} (2*sin(x)+y*cos(x)+g(y))=cos(x)+\frac{dg(y)}{dy}$

Now, let's replace the previous result into $\frac{\partial f(x,y)}{\partial y}=Q(x,y)$ :

$cos(x)+\frac{dg(y)}{dy}=cos(x)+sin(y)$

Solving for $\frac{dg(y)}{dy}$

$\frac{dg(y)}{dy}=sin(y)$

Integrating both sides with respect to y:

$g(y)=\int\ sin(y) \, dy =-cos(y)$

Replacing this result into f(x,y)

$f(x,y)=2*sin(x)+y*cos(x)-cos(y)$

Finally the solution is f(x,y)=C1 :

$2*sin(x)+y*cos(x)-cos(y)=C_1$

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4 years ago

What is the Area of the circle?

r-ruslan [8.4K]

The answer is 254.35 in square

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3 years ago

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Steve drove at a constant rate to the beach for a vacation. In the equation below, t is the time in hours it took Steve to drive

hjlf

Could you please provide the equation and the rest of the question?

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3 years ago