All categories

3 years ago

+50 points quiz

Mathematics

2 answers:

Sholpan [36]3 years ago

7 0

I was trying but they got it

Sedaia [141]3 years ago

5 0

Answer:

wasting your points but hey these are the answers

Step-by-step explanation:

1) 72

2) 2

3) 30

4) 2

You might be interested in

Which number doesn't belong?<br> 9 16 25<br> 43

Alex

Answer:

Step-by-step explanation:

Square root of 9 is 3

Square root of 16 is 4

Square root of 25 is 5

Square root of 43 is not a whole number.

8 0

3 years ago

Read 2 more answers

For whaf values of x is x^2+2x=24 true

Maru [420]

X^2 + 2x - 24 = 0
(x + 6)(x - 4) = 0
x = -6, 4

8 0

3 years ago

Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n 2 if heads comes up

Artyom0805 [142]

Answer:

In the long run, ou expect to lose $4 per game

Step-by-step explanation:

Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n^2 if heads comes up first on the nth toss.

Assuming X be the toss on which the first head appears.

then the geometric distribution of X is:

X $\sim$ geom(p = 1/2)

the probability function P can be computed as:

$P (X = n) = p(1-p)^{n-1}$

where

n = 1,2,3 ...

If I agree to pay you $n^2 if heads comes up first on the nth toss.

this implies that , you need to be paid $\sum \limits ^{n}_{i=1} n^2 P(X=n)$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = E(X^2)$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =Var (X) + [E(X)]^2$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+(\dfrac{1}{p})^2$ ∵ X $\sim$ geom(p = 1/2)

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+\dfrac{1}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p+1}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-p}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-\dfrac{1}{2}}{(\dfrac{1}{2})^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{4-1}{2} }{{\dfrac{1}{4}}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{3}{2} }{{\dfrac{1}{4}}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ 1.5}{{0.25}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =6$

Given that during the game play, You pay me $10 , the calculated expected loss = $10 - $6

= $4

∴

In the long run, you expect to lose $4 per game

3 0

4 years ago

Please help

dedylja [7]

Answer:

C ( 8,-6)

Because you move the points according to the rule.

6 0

3 years ago

Read 2 more answers

In the diagram below, and are tangent to O. Which expression gives the measure of XYZ?

zubka84 [21]

Not really sure i think its b not sure

5 0

3 years ago

Read 2 more answers