One number exceeds another number by 6. One fourth of the sum of the two numbers is two less than the smaller.
1 answer:
Answer:
7 and 13
Step-by-step explanation:
let the 2 numbers be x and y , x > y , then
x = y + 6 → (1)
(x + y) = y - 2 ( multiply both sides by 4 to clear the fraction )
x + y = 4y - 8 ( subtract 4y from both sides )
x - 3y = - 8 → (2)
Substitute x = y + 6 into (2)
y + 6 - 3y = - 8
- 2y + 6 = - 8 ( subtract 6 from both sides )
- 2y = - 14 ( divide both sides by - 2 )
y = 7
Substitute y = 7 into (1)
x = 7 + 6 = 13
The 2 numbers are 7 and 13
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Answer:
a = 2
b = 3
c = 8
Step-by-step explanation:
First, let us look at the first two (far left) fractions to solve for a.
Since , nothing needs to change in the numerator. 4 =
a = 2.
Next, we will look at the first and third fractions to solve for b.
= 32
32 / 4 = 8
= 8
b = 3
Lastly, we will solve for c.
All of these fractions simplify to 8 and are equal to each other.
c = 8
Answer:
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Step-by-step explanation:
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