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Morgarella [4.7K]
3 years ago
12

From LEAST to GREATEST order the following: 6, -4, 5, -3, 2, 8. *

Mathematics
2 answers:
madam [21]3 years ago
4 0

Answer:

-4, -3, 2, 5, 6, 8

Step-by-step explanation:

pantera1 [17]3 years ago
4 0
-4, -3, 2, 5, 6, 8, here’s your answer :)
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The mayor of a town has proposed a plan for the annexation of an adjoining community. A political study took a sample of 900 vot
Stells [14]

Answer:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

Now we can calculate the p value. Since is a bilateral test the p value would be:  

p_v= P(Z>2) =0.0228

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

Step-by-step explanation:

Information given

n=900 represent the random sample selected

\hat p=0.75 estimated proportion of residents favored annexation

p_o=0.72 is the value that we want to test

represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

The political strategist wants to test the claim that the percentage of residents who favor annexation is above 72%.:  

Null hypothesis:p\leq 0.72  

Alternative hypothesis:p > 0.72  

The statistic for this case is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the data given we got:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

Now we can calculate the p value. Since is a bilateral test the p value would be:  

p_v= P(Z>2) =0.0228

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

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OMG too difficult man!!

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