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ZanzabumX [31]
3 years ago
11

What is 458,930 rounded to the nearest ten thousand

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

459,000

Step-by-step explanation:

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What is 7p-(-5)+(-1)
nika2105 [10]
7p-(-5)+(-1)
7p+5-1
7p+4
7 0
3 years ago
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H and J are both between G and K such that GH = JK and H is between G and J.
DIA [1.3K]

Answer:

32

Step-by-step explanation:

So the order of the points is: GHJK

GH = x+10 =JK

HJ=8

JK=2x-4

JK = x+10=2x-4

x+10=2x-4

10+4=2x-x

x=14

GH= 14+10 =24

GJ = GH +HJ = 24+ 8=32

6 0
3 years ago
Find the area. The figure is not drawn to scale
poizon [28]

Answer:

96 square inches.

Step-by-step explanation:

From given picture we see that

BC=8 in

AD=10 in

Given that

AD=AB

Then AB=10 in

Apply Pythagorean theorem in triangle ABC to find AC

(hypotenuse)^2=(base)^2+(perpendicular)^2

(AB)^2=(BC)^2+(AC)^2

(10)^2=(8)^2+(AC)^2

100=64+(AC)^2

100-64=(AC)^2

36=(AC)^2

take square root

6=AC

Then area of triangle ABC =\frac{1}{2}\left(base\right)\left(altitude\right)

=\frac{1}{2}\left(8\right)\left(6\right)=24

There are total 4 congruent triangles.

Then total area of the given figure = 4(24)=96 square inches.

7 0
3 years ago
Even better morning yall
harina [27]

Answer:

48 cups

Step-by-step explanation:

4 gallons = 64 cups

1 gallon =  64 ÷ 4

1 gallon = 16 cups

3 gallons = 16 * 3 = 48 cups

6 0
3 years ago
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Use either the shell method or the disk/washer method to find the volume of the solid (Calculus Help!!!)
Rufina [12.5K]

Integrating with shells is the easier method.

<em>V</em> = 2<em>π</em> ∫₁³ <em>x</em> (√<em>x</em> + 3<em>x</em>) d<em>x</em>

That is, at various values of <em>x</em> in the interval [1, 3], we take <em>n</em> shells of radius <em>x</em>, height <em>y</em> = √<em>x</em> + 3<em>x</em>, and thickness ∆<em>x</em> so that each shell contributes a volume of 2<em>π</em> <em>x</em> (√<em>x</em> + 3<em>x</em>) ∆<em>x</em>. We then let <em>n</em> → ∞ so that ∆<em>x</em> → d<em>x</em> and sum all of the volumes by integrating.

To compute the integral, just expand the integrand:

<em>V</em> = 2<em>π</em> ∫₁³ (<em>x </em>³ʹ² + 3<em>x</em> ²) d<em>x</em>

<em>V</em> = 2<em>π</em> (2/5 <em>x </em>⁵ʹ² + <em>x</em> ³) |₁³

<em>V</em> = 2<em>π</em> ((2/5 ×<em> </em>3⁵ʹ² + 3³) - (2/5 × 1⁵ʹ² + 1³))

<em>V</em> = 4<em>π</em>/5 (9√3 + 64)

8 0
3 years ago
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