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pav-90 [236]
3 years ago
15

Find all zerosf(x)=x^4+6x^3+173x^2+332x+164​

Mathematics
1 answer:
zheka24 [161]3 years ago
6 0
The zeros are (-1,0)
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If x is 1 what is the value of y?9x - 5y = 29
mylen [45]

Given

The equation,

9x - 5y = 29.

To find the value of y when x is 1.

Explanation:

It is given that,

9x-5y=29

That implies,

When x=1,

\begin{gathered} 9(1)-5y=29 \\ 9-5y=29 \\ -5y=29-9 \\ -5y=20 \\ y=\frac{20}{-5} \\ y=-4 \end{gathered}

Hence, the value of y is -4.

4 0
1 year ago
A cylinder has a height of 12 feet and a radius of 5 feet. What is its volume? Use ​ ≈ 3.14 and round your answer to the nearest
beks73 [17]

Answer: The volume is 942 cubic feet   , 942 ft^3

Step-by-step explanation:

The formula for the volume of a cylinder is  v = pi* r^2 * h

Where v is the volume, r is the radius and h is the height.

Input the values for pi, radius, and the height into the formula to solve for the volume.

v = 3.14* (5^2) * 12

V = 3.14* 25 * 12

V = 942

7 0
3 years ago
How to graph -5\3 on a number line
Alex_Xolod [135]
<span>Number line is a way of expressing an integer into a line. 
We have the given numbers:
Let x = -5
and Let y = 3

Now let’s create line with 0 in the center. Pls. see the attached image for the number line presentation.

The answer is -2</span><span>

</span>



8 0
3 years ago
Your charges will be $75.00 per month throughout the 2 years, so at the end of that time you will have paid?
alexgriva [62]

Answer:

$1800

Step-by-step explanation:

twelve months in a year 12*2=24

75*24=1800

7 0
3 years ago
Read 2 more answers
Raíz cuadrada de 864
marshall27 [118]

Raíz cuadrada de 864

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

The general equation of ellipse is given as, x2a2+y2b2=1 x 2 a 2 + y 2 b 2 = 1 , where, a is length of semi-major axis and b is length of semi-minor axis.

centro: (0,0)

focus : (0, -√28) , (0, √28)

eje conjugado = 2√3

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

de los focos podemos obtener que: √28

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b = √3

podemos utilizar la siguiente fórmula para obtener a:

si despejamos a en la ecuación obtenemos lo siguiente:

ahora podemos sustituir los valores:

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

si graficamos la hipérbola, queda como en el documento adjunto.

To learn more hipérbola

Visit : brainly.com/question/24223341

#SPJ9

8 0
1 year ago
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