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iragen [17]
3 years ago
8

Carlos built 3 wooden toys.each toy had a mass of 5/6 kilograms. What was the total mass of the toys that he built?

Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Answer:

2.5 kg.

Step-by-step explanation:

Carlos built 3 wooden toys.

Each of the wooden toys had a mass of \frac{5}{6} kilograms.

Now, we are asked to determine the total mass of the toys that Carlos built.

Therefore, the total mass of the three toys that Carlos made will be  

(\frac{5}{6} + \frac{5}{6} + \frac{5}{6}) kg

= \frac{5 + 5 + 5}{6} kg

= \frac{15}{6} kg

= \frac{5}{2} kg

= 2.5 kg. (Answer)

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corrected question:A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random. For each of the following, find the probability that: a) both marbles are blue b) both marbles are the same color  c)the marbles are different in color

Answer:

Step-by-step explanation:

<u><em>The probability was done with replacement.</em></u>

Probaility of an event happening=\frac{number of required outcomes}{number of possible outcomes}

number of blue marbles= 2

number of green marbles=5

total number of marbles=7

(a) probability that both marbles are blue = pr(first is blue)*pr(second is blue)

                                  =\frac{2}{7}*\frac{2}{7}

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(b)probability that both marbles are the same color =pr(first is blue)*pr(second is blue) + Pr(first is green)*Pr(second is green)

   =\frac{4}{49} + \frac{5}{7}*\frac{5}{7}

   =\frac{4}{49} + \frac{25}{49}

 =\frac{29}{49}

(c)Probability that the marbles are different in colors=pr(first is blue)*pr(second is green) + Pr(first is green)*Pr(second is blue)

  =\frac{2}{7}*\frac{5}{7}+ \frac{5}{7}*\frac{2}{7}

           =\frac{10}{49}+\frac{10}{49}

      =\frac{20}{49}

6 0
3 years ago
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