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kondor19780726 [428]
4 years ago
11

I need help .pls. equations

Mathematics
2 answers:
Marina86 [1]4 years ago
6 0

Assuming you want to solve for x:

Make 15x and 15 add up to 180 in an equation since they form a straight line. A straight line is 180 degrees.

15x + 15 = 180

  • Subtract 15 from both sides.

15x = 165

  • Divide both sides by 15.

x = 11

Dmitry_Shevchenko [17]4 years ago
4 0
15 + 15 + 15x + 15x = 180

30 + 30x = 180

30x = 150

x = 5
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A pizza is divided into 30 equal pieces. Violet and Sophie each ate one sixth
erastovalidia [21]

Answer:

12.5 or 12 1/2 Slices left

Step-by-step explanation:

30 divided by 6 or (1/6) is 5

So,

Violet ate 5

Sophie ate 5 (same amount)

30 divided by 5 or (1/5) is 7.5

so we add 5+5+7.5 = 17.5 and subtract it from 30 to get our left over slices which comes up to

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hope this helps

3 0
3 years ago
Read 2 more answers
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Ugo [173]

Answer:

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Step-by-step explanation:

7 0
3 years ago
The line segments that connect 2nd base to 1st base' & 2nd base to 3rd base form a right angle. Marcus on 3rd base and he is
Stells [14]

Answer: The correct answer is option C; 90√2

Step-by-step explanation: The line segments are labelled as base 1, base 2 and base 3 respectively. This we shall call point 1, point 2 and point 3. These three points form a right angle. Also we have been told that Marcus is on point 3 and Jean is on point 2. They are both 90 feet apart. Also Joel is on point 1 and he is 90 feet away from Jean. The unmeasured distance therefore is from point 1 to point 3, which is the distance from Joel to Marcus (or Marcus to Joel).

The distance from point 1 to point 3 is the hypotenuse of the right angled triangle derived. Using the Pythagoras' theorem, the distance from  Joel to Marcus (or JM) is calculated as follows;

JM² = JC² + JL²

Where JM is the distance between Joel and Marcus (hypotenuse), JC is the distance from Jean to Marcus and JL is the distance from Jean to Joel.

JM² = 90² + 90²

JM² = 8100 + 8100

JM² = 16200

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√JM = √16200

JM = √100*√81*√2

The right hand side of the equation can be further solved as

JM = 10*9*√2

JM = 90√2

Therefore the distance between Marcus and Joel is calculated as 90√2 feet

6 0
3 years ago
Guys if you could help me in #1 #2 #3 #4
dsp73
1. $14.1
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5 0
4 years ago
Product of 2.2 and 5.00 using correct sig figs
Rashid [163]
2.2 x 5.00= 11

Lowest sig figs is 2
6 0
4 years ago
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