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2 years ago

I need help ASAP !!!! Please

Mathematics

1 answer:

ioda2 years ago

5 0

Answer:

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Step-by-step explanation:

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When an airplane leaves the runway, its angle of climb is 18 degrees and its speed is 275 feet per second. Find the plane's alti

Elodia [21]

Distance after 1 minute = speed * time = 275 * 60 = 16,500 feet
Let the altitude of the plane be y, then
sin 18 = y/16500
y = 16500 sin 18 = 5,098.78 feet

8 0

2 years ago

What is 2 to the second power

inessss [21]

2^2 = 4
just think 2 written out TWO times (hence the SECOND power).

5 0

2 years ago

Read 2 more answers

Compound Interest P = $50 r = 3.5% t = 10 years

pychu [463]

Brown oooOiejdjdjdjdieoeidididieoddo gg 1919912

4 0

2 years ago

What’s V= L times H for W

Scilla [17]

Step-by-step explanation:

It could be

V= L×B×H

Hope it helps

7 0

2 years ago

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir

Anton [14]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}= p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0204^{2})$ .

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.96$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0306^{2})$ .

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.31$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0

2 years ago