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VladimirAG [237]
2 years ago
12

R/2=(r-4)/7 how do i solve this?

Mathematics
2 answers:
rodikova [14]2 years ago
5 0
You put a value in for r, and keep trying until they equal out, let me know if this helps, or if you need more
Alik [6]2 years ago
5 0
R= -8/5
Thx hope it helps
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For brainiest:):):):)::):):):)
scZoUnD [109]

Answer:

The unit rate is accurately \frac{1}{4} (km/minute)

Step-by-step explanation:

(1,1/4) means that the vehicle traveled 1/4 km within 1 minute.

The unit rate for this problem is also known as the speed of the vehicle.

So to find the speed, you need to use distance over time.

---> Unit rate: \frac{1}{4}\\ / 1 = \frac{1}{4} (km/minute)

(2,1/2) means that the vehicle traveled 1/2 km within 2 minutes.

Same process:

---> Unit rate: \frac{1}{2} / 2 =

Because of this, the unit rate is accurately \frac{1}{4} (km/minute)

8 0
2 years ago
Which expression is the same as 10÷4?<br><br> 110 of 4<br><br> 4÷10<br><br> 110×14<br><br> 14 of 10
erica [24]

Answer:

1/4 of 10

Step-by-step explanation:

7 0
2 years ago
Help me from 6-9 (geometry)
elena55 [62]

Answer:

6) Two angles are called supplementary when their measures add up to 180 degrees. For example, two right angles are supplementary angles.

7) When the sum of two angles is equal to 90 degrees, they are called complementary angles. For example, 30 degrees and 60 degrees are complementary angles.

8) you have to plot the points on the graph and draw a line and label it with L at one point and M at another point.

9) x = 20

m < A = 65

m < B = 25

Step-by-step explanation:

9)

3x + 5 + 2x - 15 = 90

3x + 2x + 5 - 15 = 90

5x - 10 = 90

5x - 10 + 10 = 90 + 10

5x = 100

5 / 5x = 100 / 5

x = 20

A = 3x + 5

A = 3(20) + 5

A = 60 + 5

A = 65

B = 2x - 15

B = 2(20) - 15

B = 40 - 15

B = 25

8 0
3 years ago
City A is 10 miles from city B and 5 miles from city C. Cities A, B, and C form a right triangle at A. A road connects cities B
laila [671]

Answer:

11.18 miles

Step-by-step explanation:

The sides of a right triangle a, b, c are related by the equation

a^2 + b^2 = c^2

where c is the longest side of the triangle

Hence given that A connects B and C directly and forms a right angle at A

5^2 + 10^2 = c^2

Where c is the length of the road

25 + 100 = c^2

125 = c^2

c = 125^1/2

= 11.18 miles

3 0
2 years ago
Suppose sin(A) = 1/4. use the trig identity sin^2(A)+cos^2(A)=1 to find cos(A) in quadrant II. around to ten-thousandth.
larisa86 [58]

In quadrant II, \cos(A) will be negative. So

\sin^2(A) + \cos^2(A) = 1 \implies \cos(A) = -\sqrt{1 - \sin^2(A)} = -\dfrac{\sqrt{15}}4 \approx \boxed{-0.9682}

8 0
1 year ago
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