Answer:
A line that passes through (3, -8) and (7,-2).
Denote equation of that line: y = ax + b
=> Slope a can be directly determined by:
a = (7 - 3)/(-2 - -8) = 4/6 = 2/3
=> y = (2/3)x + b
This line passes (3, -8), then: -8 = (2/3)*3 + b => -8 = 2 + b => b = -10
=> y =(2/3)x - 10
There are other ways to find equation of line.
Hope this helps!
:)
Answer:
105.12
Step-by-step explanation:
you just need to multiply the length times width
Expand everything in the limit:

We have
approaching 0, and in particular
, so we can cancel a factor in the numerator and denominator:

Alternatively, if you already know about derivatives, consider the function
, whose derivative is
.
Using the limit definition, we have

which is exactly the original limit with
. The derivative is
, so the value of the limit is, again, -14.
Answer:
7y x57xhfdghff
Step-by-step explanation:
hghhhhhf