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fgiga [73]
3 years ago
10

Drag each tile to the correct box.

Mathematics
1 answer:
Dominik [7]3 years ago
8 0

Answer: your the answer is W

Step-by-step explanation:

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What is the value of X in the following: 7x-8 = 14+9x
LekaFEV [45]

Answer:

x = -11

Step-by-step explanation:

7x-8 = 14+9x

7x - 8 - 7x  -14 = 14 + 9x -7x -14

-22 = 2x

x = -11

4 0
3 years ago
Solve each equation. Show your work<br><br> 13a=-5<br> 12−b=12.5<br> -0.1=-10c
amid [387]
1) 13a=-5
Make a the subject of the formula by dividing both sides by 13(the coefficient of a)
13a/13=-5/13
Therefore a= -0.385

The second one). 12-b= 12.5
You take the 12 to the other side making b subject of the formula (-b in this case)
-b= 12.5-12
-b= 0.5
(You cannot leave b with a negative sign so you will divide both sides by -1 to cancel out the negative sign)

-b/-1= 0.5/-1
Therefore b=-0.5

The third one). -0.1= -10c
You will divide both sides by the coefficient of c(number next to c) which is -10
-0.1/-10= -10c/-10

Hence, c= 0.01
5 0
3 years ago
Help, please (single variable calculus)
balandron [24]

Hi there!

\large\boxed{ 14.875}

Our interval is from 0 to 3, with 6 intervals. Thus:

3 ÷ 6 = 0.5, which is our width for each rectangle.

Since n = 6 and we are doing a right-riemann sum, the points we will be plugging in are:

0.5, 1, 1.5, 2, 2.5, 3

Evaluate:

(0.5 · f(0.5)) + (0.5 · f(1)) + (0.5 · f(1.5)) + (0.5 · f(2)) + (0.5 · f(2.5)) + (0.5 · f(3)) =

Simplify:

0.5( -2.75 + (-3) + (-.75) + 4 + 11.25 + 21) = 14.875

7 0
3 years ago
( HELP ASAP! EASY POINTS ) The picture below shows a box sliding down a ramp:
TEA [102]

Answer:

AC = 14 cosec(68)

Explanation:

Here given:

  • angle: 68°
  • opposite: 14 ft
  • hypotenuse: AC

Use sine rule:

\rightarrow \sf sin(x) = \dfrac{opposite}{hypotenuse}

\rightarrow \sf sin(68) = \dfrac{14}{AC}

\rightarrow \sf AC= \dfrac{14}{ sin(68) }

\rightarrow \sf AC= 14  \ cosec(68)

4 0
2 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

5 0
3 years ago
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